Where R is the median between Q and L:
From my understanding of a triangle's centroid, it divides an angle bisector into parts of 2/3 and 1/3. In the given problem, these divisions are NS and SR. Therefore, twice SR would be equal to NS. From here, we can get the value of X, to solve for SR.
NS = 2SR
(x + 10) = 2(x + 3)
x + 10 = 2x + 6
x = 4
Therefore, SR = (x + 3) = 7
The perimeter is 47cm. The area would be 111cm^2. Hope this helped, could I possibly get brainliest?
Answer:
a) x = 30°
b) mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
Question:
The complete question as found on Chegg website:
In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
intercepted have the following ratio of measurements:
mRS : mST :MTU : mUR=1:4:4:3
(a) If mRS = x, then write an equation that could be used to solve for x
and find the value of x.
(b) State the measure of each of the four arcs.
mRS =
mST =
MTU
MUR =
Step-by-step explanation:
Find attached the diagram related to the question
mRS : mST : mTU : mUR = 1:4:4:3
Since mRS = x
Writing the ratios of the measure of angle in terms of mRS:
mST = 4× mRS = 4×x = 4x
mTU = 4× mRS = 4×x = 4x
mUR= 3× mRS = 3×x = 3x
The sum of measure the 4 measures of arc = 360° (sum of angle in a circle)
mRS + mST + mTU + mUR = 360°
x + 4x + 4x + 3x = 360
12x = 360
x = 360/12
x = 30°
b) The measure of angle
mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
1 yard is = to 3 feet.
20 yards = to 20 X 3 feet
your answer is 60 feet