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3 years ago

(1) Logan has 6 pounds of paste. Each time he makes dinner he uses 34 pound of

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

SHDHSB SSHD EUDXD EJDJXJEX SJDJWIDIJDWN SSHWIJJSJ

Step-by-step explanation:

XJDUXIDB DUDUU

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Each of the 6 cats in a pet store was weighed. Here are their weights (in pounds): 15, 14, 7, 13, 12, 15 Find the median and mea

Sauron [17]

The median would be 13.5 because that's the middle of all the numbers lined up from smallest to largest and the mean would be 12.7 because that's all the numbers added up divided by how many numbers there are

4 0

3 years ago

Brainliest + 20 pts to whoever helps pls!!

Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

H₀: The population variance of all commute times is equal to 4.0 minutes, i.e. σ² = 4.

Hₐ: The population variance of all commute times is not equal to 4.0 minutes, i.e. σ² ≠ 4.

The test statistic is:

$\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}$

The critical region of this test is defined as:

Reject H₀ if $\chi^{2}_{calc.}$ or $\chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}$ .

The degrees of freedom is:

$n-1=81-1=80$

Compute the critical from a Chi-square table.

$\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\$

The test statistic value is, $\chi^{2}_{calc.}=105.8$ .

$\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879$

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

6 0

3 years ago

A manufacturer makes two types of handmade fancy paper bags. Type A and Type B. Two designers a cutter and a finisher need to wo

Vlad1618 [11]

Answer:

18 Type A bags
24 Type B bags

Step-by-step explanation:

The graph shows the constraints and the boundaries of the feasible region. The maximum profit will be had with the manufacture of 18 Type A bags and 24 Type B bags.

The inequality describing the constraint on cutter hours is ...

2a +3b ≤ 108

The inequality describing the constraint on finisher hours is ...

3a +1b ≤ 78

The boundary lines of the solution regions of these inequalities intersect at ...

(a, b) = (18, 24)

The profit function is such that it doesn't pay to make all of one type or the other bags. The most profit is had for the mix ...

18 Type A bags; 24 Type B bags.

On the graph, the line representing the profit function will be as far as possible from the origin at the point of maximum profit.

4 0

3 years ago

Write an explicit formula for the sequence 7, 1, -5, -11, -17,... Then find a14

Oksana_A [137]

An=a1+d (n-1)
a1= 7
find d
Let's use a2
a2=1
1=7+d (2-1)
1=7+d
-7 both sides
d=-6
explicit formula is

an=7+-6 (n-1)

a14=?
a14=7-6 (14-1)
a14=7-6×13
a14=7-78
a14=-71

4 0

3 years ago

(3a^2b^4)^2(2ab^2) A A A A A A A A A A A

nadya68 [22]

Answer:

$18a^{5} b^{10}$

Step-by-step explanation:

5 0

3 years ago