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Illusion [34]
3 years ago
8

6-1/3x=-1 How do I do this

Mathematics
1 answer:
I am Lyosha [343]3 years ago
7 0
Im gonna assume you mean 6 - (1/3)x = -1.  Your notation is not super clear.  If so, solution is as follows:

6 - (1/3)x = -1   [subtract 6 from both sides]
-(1/3)x = -7       [multiply both sides by -3]
x = 21

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Which of the following gives a valid reason for using the given solution method to solve the system of equations shown? Equation
alukav5142 [94]

Answer:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

Step-by-step explanation:

Equation I: 4x − 5y = 4

Equation II: 2x + 3y = 2

These equation can only be solved by Elimination method

Where to Eliminate x :

We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I

Hence:

Equation I: 4x − 5y = 4 × 2

Equation II: 2x + 3y = 2 × 4

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Therefore, the valid reason using the given solution method to solve the system of equations shown is:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

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