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sergey [27]
3 years ago
13

="latex-formula">

Mathematics
1 answer:
adoni [48]3 years ago
6 0
Answer: in pic

Explanation:

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14 The straight line, L, has the equation y = 5 - 2x
lozanna [386]

Answer:

Step-by-step explanation:

(a) the co-ordinates of the point where the line crosses the y-axis,

y intercept occurs when x = 0

y = 5 - 2(0)

y = 5

(0, 5)

(b) the gradient of the line,

the general line formula is y = mx + b, where m is the slope and b is the y intercept.

y = 5 - 2x

y = -2x + 5

m = -2

(c) the equation of a line parallel to L.

Parallel lines have the same slope, but different y intercepts.

The simplest parallel line formula is

y = -2x + 0

y = -2x

7 0
2 years ago
Find a polynomial F(x) of degree 3 with real coefficients and the following zeros. 4,1-i help fast please?
Rus_ich [418]

Answer:

f(x)=x3−x2−6x2+16x−10

Step-by-step explanation:

If 3−i is a zero, then 3+i

must be a zero as they are conjugates:

f( x ) = ( x − 1 ) ( x − ( 3 − i )) ( x − ( 3 + i )) f ( x ) = ( x − 1 ) ( x2 − x ( 3 + i ) − x ( 3 − i ) + 9 + 1 ) f ( x )) ( x − 1 ) ( x2 − 6x + 10 ) f ( x ) = x3 − x 2 − 6 x 2 + 16x − 10

6 0
2 years ago
Read 2 more answers
In triangle ABC, EG = x inches and BG = (5x - 12) inches. Triangle A B C has centroid G. Lines are drawn from each point to the
yawa3891 [41]

Answer:

12. Hope this helps!!!

Step-by-step explanation:

9 0
3 years ago
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Write an equation perpendicular to y=1/5 x+9 that passes through the point (-2,-2)
Mamont248 [21]

Answer:

-2= 1/5x-2 +9

-2= -0.4 +9

Step-by-step explanation:

4 0
2 years ago
Find the area of the trapezoid.
ss7ja [257]

\bf \textit{area of a trapezoid}\\\\
A=\cfrac{h(a+b)}{2}~~
\begin{cases}
a,b=\stackrel{bases}{parallel~sides}\\
h=height\\[-0.5em]
\hrulefill\\
a=15.8\\
b=21.8\\
h=11.7
\end{cases}\implies A=\cfrac{11.7(15.8+21.8)}{2}
\\\\\\
A=\cfrac{11.7(37.6)}{2}\implies A=219.96

4 0
2 years ago
Read 2 more answers
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