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alexandr1967 [171]
4 years ago
6

Add and simplify : x+1/x+2 add 2x+15/x+2

Mathematics
1 answer:
Ierofanga [76]4 years ago
5 0
\frac{x+1}{x+2}+\frac{2x+15}{x+2} = \frac{x+1+2x+15}{x+2} =\frac{3x+16}{x+2}
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What is the volume for a cylinder with a diameter of 10 m and a height of 5 m? use 3.14 for pi
Alborosie

Answer:

V≈1570.8

Step-by-step explanation:

Radius-10

Height- 5

The answer will be V≈1570.8

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7 0
3 years ago
Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first
Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

   and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

\dfrac{a^2}{b^2}=\dfrac{A}{B}

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}

B=50 cm^2.

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(2)

In second option we have:

a=6 and b=5.

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A=77+B

\dfrac{6^2}{5^2}=\dfrac{A}{B}\\  \\\dfrac{36}{25}=\dfrac{77+B}{B}\\  \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.




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Step-by-step explanation:

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MA_775_DIABLO [31]

Answer:

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