the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
infinitely many
Step-by-step explanation:
Rewrite these equations as
y = (1/2)x + 1
2y = x + 2
and then solve the second for y: y = (1/2)x + 1. Note that these end results are identical. The two lines coincide; that is, one lies right on top of the other. Thus, there are infinitely many solutions.
Answer:
0.346
Step-by-step explanation:
brainiest pls ty
The monthly interest rate is 6%/12 = 0.5%. The interest earned each month is
0.005*$500,000 = $2500
You can withdraw $2500 each month without disturbing the principal amount.
