Answer:
![t \approx 750550.12\,yr](https://tex.z-dn.net/?f=t%20%5Capprox%20750550.12%5C%2Cyr)
Step-by-step explanation:
The time constant of the isotope is:
![\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%5Cfrac%7B1.3%5Ctimes%2010%5E%7B9%7D%5C%2Cyr%7D%7B%5Cln%202%7D)
![\tau \approx 1.876 \times 10^{9}\,yr](https://tex.z-dn.net/?f=%5Ctau%20%5Capprox%201.876%20%5Ctimes%2010%5E%7B9%7D%5C%2Cyr)
The decay of the isotope is described by the following model:
![\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bm_%7Bo%7D%7D%20%3D%20e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%20%7D)
Now, the time is cleared in the equation:
![t = -\tau \cdot \ln \frac{m}{m_{o}}](https://tex.z-dn.net/?f=t%20%3D%20-%5Ctau%20%5Ccdot%20%5Cln%20%5Cfrac%7Bm%7D%7Bm_%7Bo%7D%7D)
![t = - (1.876\times 10^{9}\,yr)\cdot \ln 0.9996](https://tex.z-dn.net/?f=t%20%3D%20-%20%281.876%5Ctimes%2010%5E%7B9%7D%5C%2Cyr%29%5Ccdot%20%5Cln%200.9996)
![t \approx 750550.12\,yr](https://tex.z-dn.net/?f=t%20%5Capprox%20750550.12%5C%2Cyr)
Answer:
(A)CPCTC
Step-by-step explanation:
Issa knows that ΔRED ≅ ΔTAN by the SSS theorem.
If two triangles are congruent, their corresponding parts will always be congruent. In fact, their corresponding angles will be equal.
Therefore, Issa concluded that ∠R ≅ ∠T by the fact that Corresponding Parts of Congruent Triangles are Congruent (CPCTC).
The correct option is A.
Similarly, we can also conclude that:
5 inches....$2700-$1200=$1500 ....$1500/$300=5
Let
x---------> radius of the cylinder
y---------> the height of the cylinder
we know that
x=2y
[surface area of cylinder]=2*[pi*r²]+2*pi*r*h
surface area=108*pi m²
r=x
h=y
x=2y
108*pi=2*[pi*(2y)²]+2*pi*(2y)*y
108*pi=8*pi*y²+4*pi*y²
108*pi=12*pi*y²
y²=108/12
y²=9----------> y=√9--------> y=3 m
x=2y-------> x=2*3-----> x=6 m
the answer is
the height of the cylinder is 3 m
Answer:
Step-by-step explanation: