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2 years ago

Simplify each expression: a)4a-3+5a b)t-3t+2t+4 c) 3(g+5)+2g d)2t+4)3+6(-5t)-(-8)

Mathematics

1 answer:

Vlad1618 [11]2 years ago

8 0

Answer:

there you go it's all the paper

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Answer ASAP plz I have 2 minutes

earnstyle [38]

250+25= 275 is your answer

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2 years ago

Please answer ASAP!!!

suter [353]

Answer:

greens

Step-by-step explanation:

if your were to get fraction stripes and line up those you can see 4/9 is the biggest. luckily i am showing you fraction strips in this answer

3 0

2 years ago

Find the zeros of the function and write in a+bi form.<br><br><br> -(x+1)^2-4=0

GrogVix [38]

Answer:

x = -(1 + 4i)

or x = -1+4i

Step-by-step explanation:

From what we have;

-(x + 1)^2 = 4

(x + 1)^2 = -4

x + 1 = √-4

x + 1 = -4i or 4i

x = -1 - 4i or -1 + 4i

3 0

2 years ago

A variable force of magnitude F(x) moves a body of mass m along the x-axis from x1 to x2. The net work done by the force in movi

kicyunya [14]

Answer:

$w=\frac{1}{2}m(v^2_2-v^2_1)$

Step-by-step explanation:

We are given that a variable force of magnitude F(x) moves a body along the x- axis from $x_1$ to $x_2$ .

The net work done by the force in moving the body from $x_1$ to $x_2$ .

$v_1$ =Velocity of the body at $x_1$

$v_2=$ Velocity of the body at $x_2$

We know that

Work done=Final kinetic energy-Initial kinetic energy

$w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1$

K.E= $\frac{1}{2}mv^2$

$Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)$

Hence, the net work done by the force is given by

$w=\frac{1}{2}m(v^2_2-v^2_1)$

3 0

3 years ago

How much does a F bring your grade down? By 0.5 or 1?

vladimir1956 [14]

Answer:

not sure different schools have different systems

Step-by-step explanation:

4 0

2 years ago