Use elimination to solve: NN+ND=50 5NN+10ND=450

1 answer:

7 0

$5NN+10ND=450\\5(NN+2ND)=450 \\ NN+2ND=90 \\ \\ \boxed{NN=90-2ND} \\ \\ NN+ND=50 =>\boxed{NN=50-ND} \\ \\ \\ 90-2ND=50-ND \\ -2ND+ND=50-90 \\ -ND=-40 \\ \\ \boxed{ND=40} \\ \\ NN=50-ND \\ NN=50-40 \\ \\ \boxed{NN=10}$

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The sum of measures of two alternate interior angles of two parallel lines with a transversal is 210°. What are the possible mea

Vladimir79 [104]

<u>Solution-</u>

If the lines are parallel, then the alternate interior angles are congruent.

As the sum of measures of the two alternate interior angles = 210°

⇒ Measure of one alternate interior angles = 105°

$So \ m\angle 1 = m\angle3=105^{\circ}= m\angle5= m\angle 7$

Since a straight angle contains 180º, the two angles forming a linear pair also contain 180º when their measures are added (making them supplementary).

$So \ m\angle 1 + m\angle2 = 180^{\circ},m\angle 3 + m\angle4 = 180^{\circ},m\angle 5+ m\angle6 = 180^{\circ} \ and \ m\angle 7 + m\angle8 = 180^{\circ}$