GCF(9; 15) = 3
9 = 3 · 3
15 = 3 · 5
9 + 15 = 3 · 3 + 3 · 5 = 3·(3 + 5)
Used distributive property: a(b + c) = ab + ac
For 0 it will equal 1 because anything to the 0th power is 1 except 0 to the 0.
For 2, It will equal for because when you raise a fraction to the negative power you flip it and that gets rid of the negative number so then you will have 2 to the second and you will get 4.
f (0) = 1, f (2) = 4
Answer:
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Refer to the diagram shown below.
Let the distance that Sassoon travels is d miles.
Let his average speed be x mph.
The time of travel is from 1 p.m. to 4 p.m., which is 3 hours.
Therefore
3x = d (1)
The distance that Archer travels is (d + 300) miles.
The time of travel is from 9 a.m. to 4 p.m., which is 7 hours.
The average traveling speed is (x + 20) mph, therefore
7(x + 20) = d + 300
That is,
7x + 140 = d + 300
7x = d + 160 (2)
Subtract (1) from (2).
7x - 3x = d + 160 - d
4x = 160
x = 40 mph (Sassoon's average speed)
x+20 = 60 mph (Archer's average speed)
From (1), obtain d = 120 mi
Answer:
Archer's speed is 60 mph.
Sassoon's speed is 40 mph.
<span>2(22-2s) + s = 23,
44 - 4s +s = 23,
-3s = -21,
s = 7, the second number.
f = 22-2s = 22 - 14 = 8, the first number?</span>