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MAVERICK [17]
3 years ago
10

What is the value of the expression below in simplest terms?

Mathematics
2 answers:
Alla [95]3 years ago
6 0
Hmm... That's hard!

Well, I ended up with 19 7/10 but I'm a bit sure its incorrect. Here's how I got my answer.

First, you look what's in the parentheses. -20 1/2. Hmm. Just that? Then look at the number outside. 4/5. Just subtract 20 1/2 and 4/5. If there was no subtraction sign, you could've just multiplied... but teachers just want to melt your brain...
Kobotan [32]3 years ago
3 0
The answer is 82/5
=16.4
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A town's population has been growing linearly. In 2003 the population was 47,000. The population has been growing by 1200 people
blsea [12.9K]

Answer:

Step-by-step explanation:

The population in 2003= 47000

Since the population increase by 1200 every year,

in 2004 the population will be 47000+1200

in 2005 the population will be 47000+(1200+1200) which is the same as

47000+2(1200) where 2 is 2 years after 2003,

Therefore the population x years after 2003 is 47000+x(1200).

P= 47000+1200x

b) The population at 2009 which is 6 years after 2003 will be

47000+(1200)*6=47000+7200= 54200

The population at 2009 is 54200,

7 0
3 years ago
A hummingbird can travel up to 15 meters per second.
Elena L [17]
Speed=15 m/s
1 hour=60 minutes
60 minutes=60 minutes (60 seconds/1 minute)=3600 seconds.

 
15 m/s=(15 m/s)(1 mile / 1609 m)(3600 s/1h)=33.56... miles/hour≈
≈33.6 miles/hour.

Answer: the speed in miles per hour would be 33.6 miles/hour
6 0
3 years ago
Read 2 more answers
Center: (-9, -3), point on circle: (-11, 2)
Vsevolod [243]

Answer:

y = -\frac{5}{2}x-\frac{51}{2}

Step-by-step explanation:

6 0
3 years ago
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Step-by-step explanation:

8 0
3 years ago
collect data (in decibels) of 10 different things in term of loudness. Arrange the data in ascending order & find mean, medi
ss7ja [257]
Whisper-20dB
Quiet Residence-30dB
Soft stereo in Residence-40dB
Average Speech-60dB
Cafeteria-80dB
Pneumatic Jackhammer-90dB
Loud crowd noise-100dB
Accelerating Bike-100dB
Rock concert-120dB
Jet Engine (75 ft away)-140dB

(1)Mode=100dB (since 100 is occurring the maximum no. of times, i.e. it has the highest frequency of 2)
(2)Mean=sum of observations/Total number of observations
=(20+30+40+60+80+90+100+100+120+140)/10
=770/10=10dB
(3)Median= 1/2[{n/2}th observation + {(n/2)+1}th observation], where, n=total no. of observations
So, 1/2[{10/2}th observation + {(10/2)+1}th observation]
=1/2[5th observation+6th observation]
=1/2[80+90]                    [Because:5th observation=80dB and 6th=90dB]
=1/2(170)
=85
Therefore, median=85dB

6 0
3 years ago
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