Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm

Width=scale÷Actual = 1/50 = 1×50 = 50cm

Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2

Area of the electronic board is 9000 cm2
Answer:

Step-by-step explanation:

Hope this will help you!!
Answer:
11
Step-by-step explanation:
The focal length is 14, and thus the sum of the lengths of the blue and red segments is also 14.
(-2, 5) Minimum
Step-by-step explanation:
y-5=(1/3)(x + 2)²
y-5=(1/3)(x²+4x+4))
y-5=1/3x²+4/3x+4/3
y=1/3x²+4/3x+4/3+5
y=1/3x²+4/3x+4/3+15/3
y=1/3x²+4/3x+19/3
graph is attached
x= -b/2a
x= (-4/3)/2(1/3)
x= (-4/3)/(2/3)
x= (-4/3)*(3/2)
3's cancel
x= (-4/1)*(1/2)
x = -4/2
x = -2
plug -2 back into
y=1/3x²+4/3x+19/3
y=1/3*4+4/3*-2+19/3
y=4/3-8/3+19/3
y=15/3
y=5
(-2,5)
if a is positive
graph looks like a smile
so minimum
if a is negative
graph looks like a frown
so maximum
quadraticswbi.weebly.com
Answer:
Step-by-step explanation: I'm assuming this problem says 56 divided by 7 times 2 in the numerator; OVER 4 to the second power in the denominator. First step would be to multiply 7 times 2, giving you 14. Thus u have 56 divided 14, which is 4. In the denominator, it says 4 to the second power, which is 16. Now u have 4 OVER 16. Now we will reduce the fraction. Both numerator and denominator have a GCF of 4. So we divide top and bottom number by 4. The end result is 1 OVER 4.