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Ugo [173]
3 years ago
7

a photographer wants to enlarge a 5x7 photo for a wall mural without distorting its width-to- length ratio. What are the largest

dimensions to which he can enlarge the photo without having its perimeter exceed 840 inches?
Mathematics
1 answer:
krok68 [10]3 years ago
6 0

The largest dimension of the enlarged photo will be: Width= 175 inches and Length= 245 inches.

<u><em>Explanation</em></u>

Dimension of the original photo is 5×7 . That means the ratio of the width to the length is 5 : 7

So, lets assume the width is 5x and length is 7x for the enlarged photo.

Formula for the perimeter of a rectangle =2(length+width)

As the perimeter of the enlarged photo should not exceed 840 inches, so...

2(7x+5x)\leq 840\\ \\ 2(12x)\leq 840\\ \\ 24x\leq 840\\ \\ x\leq \frac{840}{24}\\ \\ x\leq 35

That means the maximum value of x must be 35.

So, the largest possible width =5x=5*35=175 inches

and the largest possible length = 7x= 7*35=245 inches

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. Suppose that Scott and Bob live on the same street. In the winter, both of them like the snow on their street to be plowed. Bo
satela [25.4K]

Answer:

a. Using the inverse demand for each, solve for the social marginal benefit curve.

Bob:                          Scott:

Q = 40-P                    Q = 30 – P

(-1)Q – 40 = -P(-1)    (-1)Q – 30 = -2P

40 – Q = P             30 – Q = 2P

                             ((30 – Q) = 2P)/2

                            15 – 1/2Q = P

P = 15 – 1/2Q + 40 – Q

P = 55 – 1.5Q  

Scott is no longer willing to pay anything when Q >30

Social Marginal Benefit curve: Q = 40 - P

b. What is the socially efficient amount of plowing?

SMB = SMC

35 = 55 – 1.5Q

Subtract from both sides and rearrange

1.5Q = 20

Q = 13.33

c. Suppose the input costs of plowing fell and marginal costs of plowing were now constant at $5.

55 – 1.5Q = 5

55-5 = 1.5Q

50 = 1.5Q

33.3 = Q*

4 0
3 years ago
Find the perimeter of this figure to the nearest hundredth
Alja [10]

Answer:

The perimeter of given figure = 56.56 ft

Step-by-step explanation:

Step(i):-

From diagram

The length of the rectangle = 10 ft

The width of the rectangle = 8 ft

Perimeter of the rectangle

= 2 ( l+w)

= 2 ( 10 + 8)

= 2 × 18

= 36

Step(ii):-

The semi circle is included in the given diagram

Now we will find the perimeter of semicircle

We know that

perimeter of the circle

p = 2πr + d

perimeter of the semicircle

P = πr + 2 r (∵ d = 2 r)

Step(iii):-

From diagram the diameter of semicircle is equal to the width of the rectangle

d = 8

d = 2 r = 8

The radius of the circle 'r' = 4

perimeter of the semicircle

P = πr + 2 r

P = 3.14 ( 4) + 8

P= 20.56

Conclusion:-

The perimeter of given figure

= perimeter of rectangle + perimeter of semicircle

= 36 + 20.56

=56.56 ft

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