Question

A bicycle chain is pulled tightly so that mn is a common tangent of the gears?

Answer 1

Question: The question is incomplete. The bicycle chain diagram wasn't attached to your question. Find attached of the diagram and the answer.

A bicycle chain is pulled tightly so that mn is a common tangent of the gears. Find the distance between the centers of the gears.

Answer: The distance between the centers of the gears is 17.8 in

Explanation:

From the attached file, using Pythagoras theorem to find the value of x, we have;

h = 4.3 - 1.8

   = 2.5

x² = MN² + h²

x² = 17.6² +2.5²

x² = 309.76 + 6.25

x² = 316.01

x = √316.01

x = 17.8

Therefore, the distance between the centre of the gear is 17.8 in

Answer 2

Answer: hi your question is incomplete here is the complete question and the diagram attached

A bicycle chain is pulled tightly so that mn is a common tangent of the gears?

find the distance between the centers of the gear

Answer : 17.8 inches

Explanation:

Applying Pythagorean theorem

considering MN a tangent we will have to find x from the schematic diagram attached

H = 4.3 - 1.8 = 2.5

$x^{2} = MN^{2} + H^{2}$

    = $17.6^{2} + 2.5^{2}$

therefore X ( distance between center of gears ) = $\sqrt{17.6^{2} + 2.5^{2} }$ ≈ 17.8 inches

attached to this solution is a free hand diagram of the bicycle chain illustration