Can some one answer this
1 answer:
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Answer:
9.18% probability that a randomly selected person sleeps 6 hours or less
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected person sleeps 6 hours or less?
This is the pvalue of Z when X = 6. So
has a pvalue of 0.0918
9.18% probability that a randomly selected person sleeps 6 hours or less
Assuming you mean
first term is n=1, so 1²+3=1+3=4
2nd is n=2 so 2²+3=4+3=7
3rd is n=3 so 3²+3=9+3=12
the first 3 terms are 4,7,12
first term is n=1, so 1²+3=1+3=4
2nd is n=2 so 2²+3=4+3=7
3rd is n=3 so 3²+3=9+3=12
the first 3 terms are 4,7,12