Which linear inequality is represented by the graph ?y <1/3x-1

Mathematics

1 answer:

Natasha2012 [34]3 years ago

3 0

Here is a diagram:

In the future I would recommend Desmos Graphing Calculator

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Layna can paint a 350-square foot room in 4 hours. It takes Bebe 7 hours to paint the same room. Which equation can be used to f

ohaa [14]

The equation can be used to find the time in hours, $\dfrac{t}{4}+\dfrac{t}{7}=1$ and the time will be 2.5 hours. So the correct answer is option A.

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Layna can paint a 350-square-foot room in 4 hours.It takes Bebe 7 hours to paint the same room.

Let t be the total time taken by both to paint.They are completing 1 job so the equation will be :

$\dfrac{t}{4}+\dfrac{t}{7}=1$

Further solving it we get;

7 t + 4 t = 28

11t = 28

t = 2.5 hours.

Therefore the equation can be used to find the time in hours, $\dfrac{t}{4}+\dfrac{t}{7}=1$ and the time will be 2.5 hours. So the correct answer is option A.

To know more about equations follow

brainly.com/question/2972832

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2 years ago

Decompose the mixed number 1 3/5

Alex787 [66]

Answer: 8/5

Step-by-step explanation: 1x5+3=8/5

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2 years ago

When the velocity v of an object is very large, the magnitude of the force due to air resistance is proportional to v squared w

Sati [7]

Answer:

Step-by-step explanation:

The model fo the shell is given by the following equation of equilibrium:

$\Sigma F = -b\cdot v^{2} - m\cdot g = m\cdot \frac{dv}{dt}$

This first-order differential equation has separable variables, which are cleared herein:

$\int\limits^t_{0\,s} \, dt = -\frac{m}{b} \int\limits^{0\,\frac{m}{s} }_{600\,\frac{m}{s} } {\frac{1}{ v^{2}+\frac{m}{b}\cdot g } } \, dv$

The solution of this integral is:

$t = -\frac{m}{2b}\cdot \left[\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }\right) - \tan^{-1} \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }\right)\right]$

$\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } } \right)=-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)$

$\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\right]$

$v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m} \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } } \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m} \right) }\right]$