Ask question

Ask question

All categories

3 years ago

6

What is the value of the expression 18-2×(4 +3)

2 answers:

klio [65]3 years ago

7 0

The answer is 4 because of pemdas

Vsevolod [243]3 years ago

5 0

Do PEMDAS! P=Parentheses! E= stuff like 10 to the 1st power! M= Multiplication! D= Division! A= Addition! S= Subtraction! But a little tip, if the Subtraction is earlier on in the problem then addition then do the Subtraction first! Same with division and mum Multiplication!

You might be interested in

Which expression represents the series 1+5+25+125+625

solong [7]

So if you want to find the nth term so
1st term=1
2nd term=5
3rd term=25
we notice that 5^1=5 and 5^2=25 , but they are on the second ones so
the expression is

the nth term=5^(n-1)
so 1st term=5^(1-1)=5^0=1
2nd term=5^(2-1)=5^1=5
3rd term=5^(3-1)=5^2=25
and so on

the expression is 5^(n-1)

7 0

3 years ago

Read 2 more answers

Which of these scales are equivalent to 3cm to 4 km

sergij07 [2.7K]

Answer:

You need to add more context to the question. I cannot answer it without knowing what "These scales" are.

5 0

4 years ago

Three fishermen caught 74 fish. They divide them equally. How many are left over ?

otez555 [7]

Answer:

2 left

Step-by-step explanation:

74/3 = 24.

24*3 = 72

74-72 = 2

8 0

3 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago

Someone help -2/5 x 1/4 x 1/5

kari74 [83]

Answer:

Lol i got u homie!

-0.02

(Sorry if that wasn't a fraction but hopefully this helps)

Step-by-step explanation:

7 0

3 years ago