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rewona [7]
3 years ago
7

Your teacher is giving away candy from a bag. The bag contains 5 Reese's Peanut

Mathematics
1 answer:
scoray [572]3 years ago
4 0

Answer:

P(Snickers n Snickers)  = \frac{2}{51}

Step-by-step explanation:

Given

Bag of candy

5 Reese's Peanut Butter Cups,

4 Snickers

3 Sour Patch

6 Skittles

Required

Calculate P(Snickers n Snickers)

To solve this question, it'll be assumed that you and your friend selected snickers at a consecutive time.

First, we need to calculate the total number of candy

Total = 5 + 4 + 3 + 6

Total = 18 candies

P(Snickers n Snickers) means P(Snickers and Snickers);

i.e. the probability of selecting snicker twice

Number of snickers = 4;

So, the probability of you selecting a snicker first is \frac{4}{18}

This is gotten by dividing number of snickers by total candies.

At this point, there are 4 - 1 snickers left and there are 18 - 1 candies left;

So, the probability of your friend selecting a snicker is \frac{4 - 1}{18 - 1}.

So, P(Snickers n Snickers)  = \frac{4}{18} * \frac{4 - 1}{18 - 1}

P(Snickers n Snickers)  = \frac{4}{18} * \frac{3}{17}

P(Snickers n Snickers)  = \frac{2}{9} * \frac{3}{17}

P(Snickers n Snickers)  = \frac{2}{3} * \frac{1}{17}

P(Snickers n Snickers)  = \frac{2}{51}

<em>Hence, the probability of you and your friend choosing snickers is </em>\frac{2}{51}<em />

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