The expressions for the width, W, and area, A, of the rectangle in terms of L are:
- W =
- L - A =

The expression for the perimeter of a rectangle is given as:
P = 2(L + W)
where L is its length and W its width
a. Given that the perimeter of the rectangle is 13 feet, then;
13 = 2(L + W)
divide through by 2
= L + W
So that;
W =
- L
The required formula for the width as a function of L is: W =
- L
b. Area of a rectangle can be expressed as;
A = L * W
substitute the expression for width in that of area to have
A = L * (
- L)
=
L - 
A = 
The expression for the area A is: A = 
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Answer:
The 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Step-by-step explanation:
<u>Step :- (i)</u>
Given sample size 'n' =15
sample of the mean x⁻ = 33.2
The standard deviation of the sample 'S' = 8.3
<u>95% of confidence intervals</u>
<u></u>
<u></u>
<u>Step:-(ii)</u>
<u>The degrees of freedom γ=n-1 = 15-1=14</u>
The tabulated value t = 1.761 at 0.05 level of significance.
now substitute all possible values, we get

After calculation , we get
(33.2-3.7739 , 33.2+3.7739
(29.4261 ,36.9739)
<u>Conclusion</u>:-
the 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Answer:
d=222
Step-by-step explanation:
By exterior angle of triangle:
17x+4+8x+1=80
x=3