If n(A)=80,and n(B)=65,what is the least value of n(AuB)=? please help me friends
1 answer:
Answer:
Step-by-step explanation:
n(AUB)=n(A)+n(B)-n(A∩B)
greatest intersection of (A∩B)=65
n(A∪B)=80+65-65=80
so least value of n(A∪B)=80
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