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deff fn [24]
3 years ago
9

If the lines a and b in the diagram below are parallel why do angles 1 nd 8 measure 120 degree angles

Mathematics
1 answer:
Leto [7]3 years ago
4 0
The pairs of angles<span> on opposite sides of the transversal but outside the two lines are called </span>alternate exterior angles<span>.

</span><span>C) Because they are alternate exterior angles.</span>
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Martin had 7 pounds of grapes left, and he gave away 2/5 of them. Explain how to use compatible numbers to estimate the amount o
Dima020 [189]
<span>2/5 is close to 1/2, and it is easy to find 1/2 of 7 mentally. Half of 7 is 3.5, so Martin gave away about 3.5 pounds.</span>
7 0
4 years ago
Read 2 more answers
Find the measure of angle AEC
andreev551 [17]
Aec= 40

Explanation because it’s a 90 degree angle and dea = 50
So 90-50=40
Plea give me Brainiest
7 0
4 years ago
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Pleaseee help me. Write an equation in one variable that has no solutions. The equation must require at least one step to be sol
AnnyKZ [126]

Answer:

2x+6=6+2x

   -6    -6

2x=2x

/2   /2

x=x

No solution

Step-by-step explanation:

6 0
4 years ago
How many elements are in the set​ {x | x is an even prime​ number, x&lt;150}​?
Bond [772]

Answer:

The set {x | x is an even prime number, x<150} has 1 element.

Step-by-step explanation:

Prime Numbers: The numbers which have no factors other than 1 and the number itself are called prime numbers.  

Even Numbers are those numbers which are completely divisible by 2.

So, the only EVEN PRIME NUMBER = 2

Now, Set = {x | x is an even prime number, x<150}

So, the set has {2} as its only element.

Hence, the total elements in the set is 1.

Or, the set {x | x is an even prime number, x<150} has 1 element.

5 0
3 years ago
Given: △FKL, FK=a, m∠F=45°, m∠L=30° Find: FL
drek231 [11]

The best way to do this is to draw a picture of ΔFKL and include line segment KM that is perpendicular to FL.  This creates ΔFKM which is a 45°-45°-90° triangle and ΔLKM which is a 30°-60°-90° triangle.

Find the lengths of FM and ML.  Then, FM + ML = FL

<u>FM</u>

ΔFKM (45°-45°-90°): FK is the hypotenuse so FM = \frac{a}{\sqrt{2}} = \frac{a\sqrt{2} }{2}

<u>ML</u>

ΔLKM (30°-60°-90°): from ΔFKM, we know that KM = \frac{a\sqrt{2} }{2} , so KL = \frac{a}{\sqrt{6}} = \frac{a\sqrt{6} }{6}  

<u>FM + ML = FL</u>

(\frac{3}{3})\frac{a\sqrt{2}  }{2} + \frac{a\sqrt{6}  }{6}

= \frac{3a\sqrt{2} + a\sqrt{6} }{6}

8 0
3 years ago
Read 2 more answers
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