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timurjin [86]
3 years ago
6

2 to the power of 2 + 1 5

Mathematics
2 answers:
zzz [600]3 years ago
6 0

Answer:

2^2 + 15 = 19

Step-by-step explanation:

2 to the power of 2 literally equals 2 x 2 which is 4.

4 + 15 = 19

HOPE THIS HELPS

BRAINLIEST APPRECIATED AND PLZZ GIVE ME A THANKS

valkas [14]3 years ago
4 0

Answer:

2^2+15

4+15=19

19

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Nutka1998 [239]

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Step-by-step explanation:

If x is -1, then the point on the parabol is (-1,4)

If x is 0, then the point on the parabol is (0,-2)

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3 years ago
Which of the following is a solution of x2 − 8x = –27?
Sergeu [11.5K]
Its 4 plus i square root of eleven 
4 0
3 years ago
Read 2 more answers
Anyone please !!!!!!
IgorLugansk [536]

Answer:

4

Step-by-step explanation:

Lets start by plugging in our (a) value

a^2 + 5a + 4

(-5)^2 + 5(-5) +4

25 - 25 + 4

0 + 4

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5 0
3 years ago
Three vertices of a rectangle are (–2, 1), (–2, –3), and (4, –3)
Tpy6a [65]
The answer is C
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6 0
3 years ago
An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact
SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y  = 2 * x³ * y,

18xy = 2 * 3 * 3 * x * y,

− 10x²y = 2 * - 5 * x² * y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 * - 5 * 3 * 3 * y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

2y\left(x^3+9x-5x^2-45\right) - Factor out " (x^3+9x-5x^2-45\right)) " by grouping,

\left(x^3-5x^2\right)+\left(9x-45\right) - Factor 9 from 9x - 45 and x² from x³ - 5x²,

9\left(x-5\right)+x^2\left(x-5\right) - Factor out common term x - 5,

\left(x-5\right)\left(x^2+9\right) - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0
3 years ago
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