There are 28 ways in which a couple can choose the name of the baby for its name.
<h3>What is defined as the combination?</h3>
- A combination is an algebraic technique for determining the number of possible arrangements in a set of items in which the order of the selection is irrelevant.
- You can choose the items in just about any order in combinations. Permutations and combinations are often confused.
If we need to choose objects from two groups of x and n objects so that one object from each group is chosen, we can do so by calculating the combinations possible by:
= ˣC₁ × ⁿC₁
Let 'x' be the set of first name = 7
Let 'n' be the set of second name = 4
Putting the values in formula;
= ⁷C₁ × ⁴C₁
= 7 × 4
= 28
Thus, there are 28 ways in which a couple can choose the name of the baby for its name.
To know more about the combination, here
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The complete question is-
A couple has narrowed down the choices of a name for their new baby to 7 first names and 4 second names.
How many different first- and second-name arrangements are possible?
Answer:
it should be b
Step-by-step explanation:
Put the coordinates of the points to the equations of the functions and check:
for (1, 4)
y = 5x + 4 → 4 = 5(1) + 4 → 4 = 5 + 4 → 4 = 9 FALSE
y = (x + 1)² → 4 = (1 + 1)² → 4 = 2² → 4 = 4 CORRECT
y = (x + 3)² → 4 = (1 + 3)² → 4 = 4² → 4 = 16 FALSE
y = 7x - 5 → 4 = 7(1) - 5 → 4 = 7 - 5 → 4 = 2 FALSE
Only y = (x + 1)².
Check other points:
for (2, 9)
9 = (2 + 1)² → 9 = 3² → 9 = 9 CORRECT
for (3, 16)
16 = (3 + 1)² → 16 = 4² → 16 = 16 CORRECT
<h3>Answer: Only y = (x + 1)²</h3>
Answer:
20 days
Step-by-step explanation:
Number of books sold each day for 40 days :
The first quartile (Q1) = 2
For the 25% of the days = 2 books were sold
Hence 0.25 * 40 = 10 days, 2 books or less were sold
The upper quartile (Q3) = 12 books
For up to 75% of the days = 0.75 * 40 = 30 days ; 12 books or less were sold
To obtain the number of books sold between 2 and 12 ; we subtract :
(30 days - 10 days) = 20 days