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damaskus [11]
3 years ago
11

If the corresponding angles of two triangles are congruent, then the two triangles are _____.

Mathematics
2 answers:
konstantin123 [22]3 years ago
8 0

Answer:

D. Similar

Step-by-step explanation:

Corresponding angles don't have to be equal to be congruent. You have to look and see if all the angles are the correct proportions in each triangle to see if they are congruent or not.  There are a few measuring techniques that use congruent triangles to find the answer.

I also probably understand that this was a bit late for answering so I do apologize.

kotykmax [81]3 years ago
7 0
Equal is the answer.  


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Is -9.2222 a irrational number? Or rational? Im so confused
finlep [7]

Answer:

  rational

Step-by-step explanation:

Any number that can be written with a finite number of digits is rational. The given number is rational. (It has 5 digits.)

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Any repeating decimal is rational.

If this were -9.2222..., it would be -9 2/9 = -83/9, also a rational number.

_____

A number is irrational if it cannot be represented exactly as a decimal or repeating decimal. That is, its decimal fraction part continues forever without repeating.

5 0
4 years ago
WILL GIVE BRAINLY!!!! describe the types of correlation between two variables on a graph
Crazy boy [7]

Negative Correlation - These variables point towards the left making them negative.

Positive Correlation - These variables point towards the right making them positive.

No Correlation - These variables have the same x coordinates or same y coordinates.

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5 0
3 years ago
Read 2 more answers
4. When Megan solved this system using the elimination method, she added the equations together and got the equation 4y = 16. Th
Ede4ka [16]
Hi there!

So, our two equations are:
2x + 3y = 20 and
-2x + y = 4

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Divide 24 by 4, which is 6.

y = 6, then we plug that in to the first equation for y:
2x + 3(6) = 20
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So, she made her first mistake when adding the equations, adding 20 and 4, she somehow got 16. 

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6 0
3 years ago
A survey was conducted on the salaries of 30 randomly selected households in two different cities.
aliya0001 [1]
I think
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4 0
3 years ago
Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
3 years ago
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