Find the circumference of the circle.

a distribution for the last difit of phone numbers sampled from a phone book for the phone number 968-9667 the last difit 7 woul

lisov135 [29]

Answer:

The answer is "Option D".

Step-by-step explanation:

Please find the attached file of the complete question:

In this question, the last choice "Histogram IV" is correct because it would be roughly evenly distributed.

7 0

3 years ago

In a clinical trial of 268 subjects treated with a drug, 11% of the subjects reported dizziness. The margin of error is plus o

Mariulka [41]

Answer:

$\hat p =0.11$ represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

$\hat q = 1-\hat p = 1-0.11= 0.89$ represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

$\alpha= 1-0.90 =0.1$ and this value represent the significance level of the test or the probability of error type I

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$