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Wewaii [24]
3 years ago
9

A​ ​piece​ ​of​ ​rope​ ​94.2​ ​inches​ ​long​ ​will​ ​enclose​ ​a​ ​circular​ ​child’s​ ​wading pool. What​ ​is​ ​the​ ​diameter

​ ​of​ ​the​ ​pool?
Mathematics
1 answer:
Elis [28]3 years ago
4 0
The circumference of a circle is pi times D. So, 94.2/pi = 29.98 or about 30 in
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Answer:

x = - 1

Step-by-step explanation:

\frac{3}{4} (8x + 12) = 3 ( multiply both sides by 4 to clear the fraction )

3(8x + 12) = 12 ( divide both sides by 3 )

8x + 12 = 4 ( subtract 12 from both sides )

8x = - 8 ( divide both sides by 8 )

x = - 1

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vovangra [49]

Answer:

1. 27^{\frac{2}{3} } =9

2. \sqrt{36^{3} } =216

3. (-243)^{\frac{3}{5} } =-27

4. 40^{\frac{2}{3}}=4\sqrt[3]{25} =4325

5. Step 4: (\frac{343}{27}) ^{-1} =\frac{27}{343}

6. D. -72cd^{7}

Step-by-step explanation:

Use the following properties:

a^{\frac{x}{y} } =\sqrt[x]{a^{y} }

\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

a^{-n} =\frac{1}{a^{n} }

(xy)^{z} =x^{z} y^{z} \\\\

(x^{y}) ^{z} =x^{yz}

x^{y} x^{z} =x^{y+z}

So:

1. 27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9

2. \sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36}  \sqrt{36} =6*6*6=216

3. (-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27

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5. (\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}

6.

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3 years ago
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