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OLga [1]
3 years ago
6

What is the missing cotangent data (cot) in the picture?

Mathematics
1 answer:
pshichka [43]3 years ago
5 0

Step-by-step explanation:

<em>Look at the picture.</em>

Hmm.... If the angle θ is correctly marked on your photo, then your solution is incorrect.

You write the function values ​​but for the angle 180° - θ.

\sin(180^o-\theta)=\sin\theta\\\cos(180^o-\theta)=-\cos\theta\\\tan(180^o-\theta)=-\tan\theta\\\cot(180^o-\theta)=-\cot\theta

Therefore

for

x=-7,\ y=24,\ r=\sqrt{(-7)^2+24^2}=\sqrt{49+576}=\sqrt{625}=25

Let θ be this angle in your picture.

\sin\theta=\dfrac{24}{25}\\\\\cos\theta=-\dfrac{-7}{25}=\dfrac{7}{25}\\\\\tan\theta=-\dfrac{24}{-7}=\dfrac{24}{7}\\\\\cot\theta=-\dfrac{-7}{24}=\dfrac{7}{24}\\\\\sec\theta=\dfrac{1}{\cos\theta}=\dfrac{1}{\frac{7}{25}}=\dfrac{25}{7}\\\\\csc\theta=\dfrac{1}{\sin\theta}=\dfrac{1}{\frac{24}{25}}=\dfrac{25}{24}

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Question, I that the Algebra nation book????
3 0
3 years ago
Solve the equation. dy dx = ay + b cy + d , where a, b, c, and d are constants. (assume a ≠ 0 and ay + b ≠ 0.)
Reil [10]

 

It solves it in x. the solution for y includes heavy use of the product log function.

dy/dx                                = ay + b/cy +d

(cy +d/ ay + b) dy            = dx

∫ (cy +d/ ay + b) dy          = x (t) + C

 

Into solving the integral, integration by parts followed by u substitution and another integration by parts.

 

∫ (cy +d/ ay + b) dy

u            = cy + d dv          = dy/ay + b

du          = c dy v               = ln I ay + b l / a

 

Then, use u substitution for the new integral

 

u            = ay + b

du          = a dy

∫ ln l ay + b I dy                = ∫ ln IuI /a du    = 1/a ∫ ln luI du

 

Integrating the natural log includes thus far another integration by parts

r             = ln IuI ds            = du

dr          = du / u (s)           = du

∫ ln IuI / du                         = u ln IuI - ∫ du   = u ln IuI - ∫ a dy                                                                                   = (ay + b) ln Iay +bl – ay

 

The original integral of expression

∫ (cy +d/ ay + b) dy             = cy + d/a ln lay+bl – c/a² [(ay+b) ln lay+bl – ay]

Then simplify

∫ (cy +d/ ay + b) dy             = cy + d/a ln lay+bl – c/a²[(ay+b) ln lay+bl – ay]

                                           = a (cy + d)/a² ln lay+bl – c (ay+b)/ a²ln lay+bl +                                                               c/a² ay

                                           = cay + ad – cay – cb/ a² ln lay+bl + cay/a²

                                           = ad – cb/a²ln lay+bl + cy/a

 The final answer will be

x(t) + C                               = ad – cb/a² ln lay+bl + cy/a

x(t)                                     = ad – cb/a² ln lay+bl + cy/a + k

 

<span> </span>

3 0
3 years ago
4(x+1) - 7 = 3(x-1) + x
alisha [4.7K]

Answer:

do you need it to be simplified?

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3 years ago
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Ede4ka [16]
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The value of y varies directly as x, with a constant of variation of -8. What is the value of y when x is 7?
slega [8]

Answer:

y = -56

Step-by-step explanation:

The equation for direct variation is

y = kx  where k is the constant of variation

y = -8 x

We know x =7

y = -8*7

y = -56

6 0
3 years ago
Read 2 more answers
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