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OLga [1]
3 years ago
6

What is the missing cotangent data (cot) in the picture?

Mathematics
1 answer:
pshichka [43]3 years ago
5 0

Step-by-step explanation:

<em>Look at the picture.</em>

Hmm.... If the angle θ is correctly marked on your photo, then your solution is incorrect.

You write the function values ​​but for the angle 180° - θ.

\sin(180^o-\theta)=\sin\theta\\\cos(180^o-\theta)=-\cos\theta\\\tan(180^o-\theta)=-\tan\theta\\\cot(180^o-\theta)=-\cot\theta

Therefore

for

x=-7,\ y=24,\ r=\sqrt{(-7)^2+24^2}=\sqrt{49+576}=\sqrt{625}=25

Let θ be this angle in your picture.

\sin\theta=\dfrac{24}{25}\\\\\cos\theta=-\dfrac{-7}{25}=\dfrac{7}{25}\\\\\tan\theta=-\dfrac{24}{-7}=\dfrac{24}{7}\\\\\cot\theta=-\dfrac{-7}{24}=\dfrac{7}{24}\\\\\sec\theta=\dfrac{1}{\cos\theta}=\dfrac{1}{\frac{7}{25}}=\dfrac{25}{7}\\\\\csc\theta=\dfrac{1}{\sin\theta}=\dfrac{1}{\frac{24}{25}}=\dfrac{25}{24}

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Answer:

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Step-by-step explanation:

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3 years ago
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Anni [7]

a. The water in the second tank decreases at a faster rate than the water in the first tank. The initial water level in the first tank is greater than the initial water level in the second tank.

Step-by-step explanation:

Step 1:

It is given that the time remaining in first tank is given by the equation y = -10x + 80. We can get the total water in the tank by substituting x = 0 in the equation. The total volume of water in first tank is 80 litres.

Step 2:

The value of y in the equation y = -10x + 80 will be 0 when the tank is fully empty. When y = 0 , 10x = 80, so x = 8. We can conclude that the first tank empties fully in 8 minutes.

In 8 minutes 80 litres of water is emptied from first tank. So the water in the first tank decreases at  rate of 80 / 8 = 10 litres per minute

Step 3:

As per the given table for the second tank, 60 litres of water remains when x =0. So the total volume of water in the second tank = 60 litres.

Step 4:

As per the given table for the second tank, the volume becomes 0 in 5 minutes. In 5 minutes 60 litres of water is emptied from second tank. So the water in  second tank decreases at rate of 60 / 5 = 12 litres per minute.

Step 5:

The initial volume of water in first tank is higher. The water in  second tank decreases at a faster rate than the first tank.

Step 6:

The only correct option is:

a. The water in  second tank decreases at a faster rate than the water in the first tank. The initial water level in  first tank is greater than the initial water level in the second tank.

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