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d1i1m1o1n [39]
3 years ago
12

Is subtraction of decimals associative? If not, give a counter example.

Mathematics
1 answer:
Masteriza [31]3 years ago
4 0
Associative property is only applied to addition and multiplication. Thus, it can't be applied to subtraction. This property is manifested when you get the same answer no matter where you put the parenthesis. Example of associative property is:

(50 + 2) + (92 + 6) = 52+98 = 150
50 + (2+92) + 6 = 50 + 94 + 6 = 150

Here is the counter example for the subtraction of decimals:

(3.45 - 8.92) - (1.9 - 7.3) = -5.47 - ⁻5.4 = -0.07
3.45 - (8.92 - 1.9) - 7.3 = 3.45 - 7.02 - 1.9 = -5.47
As you can see, the answers are not the same.
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What expressions are equivalent to 4(4a+5)
Firlakuza [10]

Answer:

<h3>16a + 20</h3>

Step-by-step explanation:

4(4a + 5)         <em>use distributive property</em>

= (4)(4a) + (4)(5) = 16a + 20

5 0
3 years ago
5.
tresset_1 [31]
A and D because it is basically saying 3:36 so when you simplify it comes down to 1:12
8 0
2 years ago
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Find the Function and Solution.
ser-zykov [4K]

Answer:

y= (-7/16)

Step-by-step explanation:

Multiply (3/4)(1/4)= (3/16)

y= (3/16)-(5/8)

y= (-7/16)

I hope this is right, im not 100% sure

4 0
2 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
3 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places).
statuscvo [17]

Answer:

The values of given function are shown in the below table.

Step-by-step explanation:

The given function is

f(x)=\frac{x^2-5x}{x^2-x-20}

Simplify the given function.

f(x)=\frac{x(x-5)}{x^2-5x+4x-20}

f(x)=\frac{x(x-5)}{x(x-5)+4(x-5)}

f(x)=\frac{x(x-5)}{(x+4)(x-5)}

Cancel out the common factor.

f(x)=\frac{x}{x+4}

Substitute x=5.5 in the above equation.

f(5.5)=\frac{5.5}{5.5+4}

f(5.5)=\frac{5.5}{9.5}

f(5.5)=0.57894736842

f(5.5)\approx 0.578947

Similarly find the value for all values of x.

The values of given function are shown in the below table.

8 0
3 years ago
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