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RSB [31]
4 years ago
5

Factor 5(x^2n-1)·(2x^3n 1)^2

Mathematics
1 answer:
nikdorinn [45]4 years ago
3 0

I think I may be wrong check

5(x^2n-1)×(2x^3n-1) ^2

=20n3 x8 -20n2 x5 +20n x3 +20n x3 +5n x2-5

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The product of 16 and the variable p
Tresset [83]

Answer:

16p

Step-by-step explanation:

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3 years ago
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Can you order these please?
Nadusha1986 [10]
By making each of these a decimal, it's easier to see which are bigger or smaller

2.1, 2 2/5, 2 1/2, 2.6, 2.95

2 2/5 = 2.4
2 1/2 = 2.5
4 0
3 years ago
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What is 6/10 as hundredths in fraction form
Step2247 [10]
To get in hundredths form you need to multiply both the numerator and denominator by 10. 6×10=60 and 10×10=100
The answer is 60/100
7 0
3 years ago
Luis
Scorpion4ik [409]

Answer:

Espero y esto te ayude :) si me falto algo lo siento.

Step-by-step explanation:

Si se oferta un producto al 10% de descuento, esto significa que el precio final del producto será 90% del precio original. Para hallar estos datos, debemos usar una regla de tres, de la siguiente forma:

100% 90%

-------------------- → ---------------------------

Precio Original Precio con Descuento?

SARAPES

- Ana: descuento (14), precio rebajado 126

Precio rebajado = 140.90 / 100 = 126

Descuento: 140 - 126 = 14

- Javier: descuento (8), precio rebajado 72

Precio rebajado = 80.90 / 100 = 72

Descuento: 80 - 72 = 8

ARETES

- Luis: descuento (5), precio rebajado 72

Precio rebajado = 50.90 / 100 = 45

Descuento: 50 - 45 = 5

- Ana: Precio original (60) , descuento (6), precio rebajado 54

Precio original: X.0,10 = 6

X = 60

Precio rebajado: 60 - 6 = 54

- Javier: Precio original (40) , descuento (4), precio rebajado 36

Precio original: X.0,10 = 4

X = 40

Precio rebajado: 40 - 4 = 36

6 0
3 years ago
What is the step by step process of this question
drek231 [11]
Hello there!

In order to solve this system of equations, you would first need to make one equation have a negative variable.

2a + 3b = -1
(3a + 5b = -2) -1

2a + 3b = -1
-3a - 5b = 2

Now, we have to modify the equations for it to be able to cancel out a variable. To do this, you would need to look at the least common multiple.

2: 2, 4, 6, 8, 10
3: 3, 6, 9, 12, 15

One least common multiple would be 6 so let's modify the equation!

(2a + 3b = -1) 3
(-3a - 5b = 2) 2

6a + 9b = -3
-6a - 10b = 4

Now, let's cancel out the variable and solve for b.

9b = -3
-10b = 4

-1b = 1
b = -1

In order to solve for a, just plug in the b into one equation and solve for a.

2a + 3(-1) = -1
2a - 3 = -1
2a = 2
a = 1

The answer would be a = 1 and b = -1


7 0
4 years ago
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