3 years ago

Factor 5(x^2n-1)·(2x^3n 1)^2

Mathematics

1 answer:

nikdorinn [45]3 years ago

3 0

I think I may be wrong check

5(x^2n-1)×(2x^3n-1) ^2

=20n3 x8 -20n2 x5 +20n x3 +20n x3 +5n x2-5

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PLEASE I REALLY NEED YOUR HELP!

Ivenika [448]

Answer:

x = 28

m∠ACD = 68°

Step-by-step explanation:

∠BAE ≅∠DAC because they are vertical angles

∠ACD = 180 - 124 = 56°

to find 'x': 56 + 2x + (180 - 4x) = 180

236 - 2x = 180

-2x = -56

x = 28

m∠ACD = 180 - 4(28) = 180 - 112 = 68°

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