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3 years ago

What is the length of the line

Mathematics

1 answer:

Sergio039 [100]3 years ago

5 0

B. 7

Hope this helps! :)

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Someone explain it please

Alina [70]

9514 1404 393

Answer:

∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

84° +(x +59)° +(x +51)° = 180°

(2x + 194)° = 180° . . . collect terms

2x = -14 . . . . . . . . . . divide by °, and subtract 194

x = -7 . . . . . . . . . . . .divide by 2

Now, the measure of angle A is ...

∠A = (x +51)° = (-7 +51)°

∠A = 44°

4 0

3 years ago

To solve y and x, I am adding a picture

Viktor [21]

Answer:

$x =\sqrt 5$

$y = \sqrt{5$

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

$\cos(45) = \frac{y}{\sqrt{10}}$ --- cosine formula i.e. adj/hyp

Solve for y

$y = \sqrt{10} * \cos(45)$

In radical form, we have:

$y = \sqrt{10} * \frac{1}{\sqrt 2}$

$y = \sqrt{10/2}$

$y = \sqrt{5$

To solve for x, we make use of Pythagoras theorem

$x^2 + y^2 = (\sqrt{10})^2$

$x^2 + y^2 =10$

Substitute for y

$x^2 + (\sqrt 5)^2 =10$

$x^2 + 5 =10$

Collect like terms

$x^2 =10-5$

$x^2= 5$

Solve for x

$x =\sqrt 5$

4 0

3 years ago

N 1968, it cost $54,000 for a 30-second commercial during the Super Bowl. In 1973, the cost for a 30-second commercial was $88,0

madreJ [45]

In 5 years, the price increased about 30%.
I am not good at perentages, so correct me if I'm wrong. Also this is an estimation, not the exact percentage.

8 0

3 years ago

A bag contains 4 red marbles and 5 blue marbles. If two marbles are chosen at random, one at a time and without replacement, wha

kari74 [83]

P(red) 4/9 on the first pull, P(red) 3/8 on the second pull
(4/9)(3/8) = 12/72 = 1/6 Letter D

6 0

3 years ago

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Carly is constructing the inscribed circle for △MNP . She has already used her compass and straightedge to complete the part of

arlik [135]

The complete question in the attached figure

the answer is Place the point of the compass on point J and draw an arc in the interior of the triangle.

4 0

3 years ago