How do you do 4x^2+3x-10=0

1 answer:

8 0

$4x^2+3x-10=0\\
4x^2+8x-5x-10=0\\
4x(x+2)-5(x+2)=0\\
(4x-5)(x+2)=0\\
x=\dfrac{5}{4} \vee x=-2
$

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