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Grace [21]
4 years ago
8

How do you do 4x^2+3x-10=0

Mathematics
1 answer:
Likurg_2 [28]4 years ago
8 0
4x^2+3x-10=0\\
4x^2+8x-5x-10=0\\
4x(x+2)-5(x+2)=0\\
(4x-5)(x+2)=0\\
x=\dfrac{5}{4} \vee x=-2

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A jar of natural peanut butter normally cost four dollars today it's on sale for $3.60 what is the percentage of the discount
kakasveta [241]
$4 is the original price of the jar consisting of peanut butter so therefor it = 100%. It's for sale at $3.60, so we divide $4 by 100% so we get the percentage for each cent and then we times it by 3.60 to get the percentage for $3.60 which is 90%. Now we subtract 90% from 100% to get the discounted percentage for 40cents :)

5 0
3 years ago
30 points and BRAINLIEST!
Ghella [55]

Answer:

(x − 4)² + (y − 3)² = 25

Step-by-step explanation:

The equation of a circle is:

(x − h)² + (y − k)² = r²

Given three points on the circle, we can write three equations:

(1 − h)² + (7 − k)² = r²

(8 − h)² + (6 − k)² = r²

(7 − h)² + (-1 − k)² = r²

Expanding:

1 − 2h + h² + 49 − 14k + k² = r²

64 − 16h + h² + 36 − 12k + k² = r²

49 − 14h + h² + 1 + 2k + k² = r²

Simplifying:

50 − 2h + h² − 14k + k² = r²

100 − 16h + h² − 12k + k² = r²

50 − 14h + h² + 2k + k² = r²

Subtracting the first equation from the second and third equations:

50 − 14h + 2k = 0

-12h + 16k = 0

Solving the system of equations, first reduce:

25 − 7h + k = 0

-3h + 4k = 0

Solve with substitution or elimination.  Using substitution, solve for k in the first equation and substitute into the second.

k = 7h − 25

-3h + 4(7h − 25) = 0

-3h + 28h − 100 = 0

25h = 100

h = 4

k = 7h −25

k = 7(4) − 25

k = 3

Now plug these into any of the original three equations to find r.

(1 − h)² + (7 − k)² = r²

(1 − 4)² + (7 − 3)² = r²

9 + 16 = r²

25 = r²

The equation of the circle is:

(x − 4)² + (y − 3)² = 25

Graph: desmos.com/calculator/ctoljeqhnp

6 0
3 years ago
A car travels at 45 miles per hour how long did it travel in 4 hours?
wolverine [178]

Answer:

180 miles

Step-by-step explanation:

just multiple 45X4

7 0
3 years ago
Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed
Ad libitum [116K]

Answer:  The answer is 7\dfrac{7}{8} ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.

We can see that

b_1-b_0=b_2-b_1=\dfrac{11}{8}.

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.

Thus, the weight of the puupy after 3 weeks will be

b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.

5 0
4 years ago
Read 2 more answers
Which value of x makes the numerical sentence true? 25^ 1/2 × 5 ^–3 = 5 ^x
Elenna [48]
5^-3=0.008
1/2=0.5
0.5*0.008=0.004
5/0.004=1250
5 0
4 years ago
Read 2 more answers
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