Question

1.Find the coordinates of the midpoint of __ given that H (-1,3) and X (7,1).

Answer 1

Answer:

1. (3, 2)

2. Option C. 12.2

3. Option A. 165 units

Step-by-step explanation:

1. The midpoint of two coordinates (x₁, x₂) and (y₁, y₂) is calculate by,

$(x, y) = (\frac{x_{1} + x_{2}}{2},\frac{y_{1} + y_{2}}{2})$

⇒$(x, y) = (\frac{-1 + 7}{2},\frac{3 + 1}{2})$

Thus (x, y) = (3, 2)

Hence, none of given options are true.

2. The distance between two coordinates is calculate by,

$Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2$

⇒ Distance = 12.16 ≈ 12.2 unit

Hence, option (C) is correct.

3. The distance between T(80, 20) and V(110, 85) is comparatively smaller than T(80, 20) and U(20, 60).

Using the Distance formula,

$Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2$

Distance between T(80, 20) and V(110, 85) is 71.59 unit

and Distance between U(20, 60) and V(110, 85) is 93.41 unit

So, Airplane firstly go to point V from point T and then point U.

Total shortest distance = 71.60 + 93.40 = 165 unit.

Hence, option (A) is correct.

Answer 2

1. B. 2.C 3.C.    these answers are all correct.