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Archy [21]
3 years ago
11

Find the sum of the first 50 terms. -6,-2,2,6...

Mathematics
1 answer:
Delicious77 [7]3 years ago
3 0
This is an arithmetic sequence with a1 = -6 and d = 4

Sn  = (n/2) (2a1 + (n-1)d)

S50  = (50/2)[2*-6 + (50-1)*4]

        =  25 * (-12 + 4*49)

        =    4600


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FrozenT [24]
It only has one line of symmetry
8 0
3 years ago
I need the answer fast please
iogann1982 [59]

Answer:

A'

Step-by-step explanation:

It is A' because they are corresponding angles, it is the same exact shape it has just been translated to a different area of the graphic plane.

If my answer is incorrect, please notify me and I'll assess what it was that I did wrong.

3 0
3 years ago
3. If the mZLKI - 174º and KR bisects LLKI, then find the mLLKR.
lisov135 [29]
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7 0
3 years ago
Find the outward flux of the vector field f=(x3,y3,z2) across the surface of the region that is enclosed by the circular cylinde
ahrayia [7]
Use the divergence theorem.

\mathbf f(x,y,z)=(x^3,y^3,z^3)\implies \nabla\cdot\mathbf f=3(x^2+y^2+z^2)

Calling the closed region \mathcal R and its boundary the surface \partial\mathcal R, we have by the divergence theorem,

\displaystyle\underbrace{\iint_{\partial\mathcal R}\mathbf f\cdot\mathrm d\mathbf S}_{\text{flux}}=\iiint_{\mathcal R}\nabla\cdot\mathbf f\,\mathrm dV

We set up the volume integral in cylindrical coordinates, using

\begin{cases}x=u\cos v\\y=u\sin v\\z=w\end{cases}\implies\mathrm dV=u\,\mathrm du\,\mathrm dv\,\mathrm dw

\displaystyle\iiint_{\mathcal R}\nabla\cdot\mathbf f\,\mathrm dV=3\int_{w=0}^{w=6}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=8}(u^2\cos^2v+u^2\sin^2v+w^2)u\,\mathrm du\,\mathrm dv\,\mathrm dw
=6\pi\displaystyle\int_{w=0}^{w=6}\int_{u=0}^{u=8}(u^3+uw^2)\,\mathrm du\,\mathrm dw=50,688\pi
7 0
3 years ago
A functionf(x) is graphed on the coordinate plane.
mario62 [17]

Answer:

y = -1/2x + b  meaning f(x) = -1/2x + b

Step-by-step explanation:

Use two points on the graph that you can find the value of  or use Slope = raise/run

let use points (2,0) and (0, 1)

slope = (change in the y-value)/(change in the x-value.

slope = (1 - 0)/(0 - 2)

slope = 1/-2 or -1/2

Or starting at point (2, 0) the run(x movement) = -2 and the raise is 1.

slope = raise/run

slope =  1/-2 or -1/2

Using one point (2,0) and the slope of -1/2, substitute into the slope intersect form, y = mx + b, and solve for "b" .

y= mx + b

0 = -1/2(2) + b

0 = -1 + b

1 = b

Now write your equation: y = mx +b where m = -1/2 and b = 1

y = -1/2x +b

3 0
3 years ago
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