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fiasKO [112]
3 years ago
12

The figure below shows a shaded circular region inside a larger circle: A shaded circle is shown inside another larger circle. T

he radius of the smaller circle is labeled as r and the radius of the larger circle is labeled as R. On the right side of the image is written r equal to 2 inches and below r equal to 2 inches is written R equal to 5 inches. What is the probability that a point chosen inside the larger circle is not in the shaded region? A)84% B)50% C)42% D)16%
Mathematics
2 answers:
Aleks [24]3 years ago
7 0
Short answer: 84% A
Remark
This sounds like there are only 2 circles that matter. The small one is inside the larger and the small one is shaded.

Step One
Find the area of the small circle.

<em>Givens</em>
r = 2
pi = 3.14

<em>Formula</em>
A = pi*r*r = pi r^2

<em>Sub and Solve</em>
A = 3.14 * 2^2
A = 12.56

Step Two
Find the area of the larger circle
A = pi*r^2
pi = 3.14
r = 5

Area = 3.14 * 5^2
Area = 3.14 * 25
Area = 78.5

Step Three
Find the area of the unshaded region between the larger and smaller circles.

<em>Formula</em>
Area unshaded region = Area of the Large Circle - The area small circle

<em>Givens</em>
Area Large Circle = 78.5
Area Small Circle = 12.56

<em>Solve</em>
Area of unshaded region = 78.5 - 12.56 = 65.94

Find the probability of a point being in the unshaded region.

P(unshaded region) = (Area of Unshaded region / Entire Area)*100%
P(unshaded region) = (65.94 / 78.5) *100%
P(unshaded region) = 84%

Answer: A <<<< 84%


Taya2010 [7]3 years ago
3 0
Area of larger circle:  3.14 x 5^2 = 78.5

Area of small circle: 3.14 x 2^2 = 12.56

Difference of the 2 areas: 78.5 - 12.56 = 65.94

Probability of being in large circle but not small circle: 65.94 / 78.5 = 0.84 = 84%


 The answer is A) 84%

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Westley and Buttercup are each saving money. Westley starts with $85 in in his savings and add $5 per week (y=85+5x)
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Answer:

After 5 weeks.

Step-by-step explanation:

Westley starts with $85 and saves $5 per week. So:

y=85+5x

Buttercup starts with $10 and saves $20 per week. So:

y=10+20x

When they have the same amount of money, the two equations will be equal to each other. Therefore:

85+5x=10+20x

Solve for x. Subtract 10 from both sides:

75+5x=20x

Subtract 5x from both sides:

75=15x

Divide both sides by 15:

x=5

Westley and Buttercup will have the same amount of money after 5 weeks.

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2 years ago
Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.
alina1380 [7]

Answer:

v_1=(\frac{1}{10},-\frac{3}{10})

v_2=(-\frac{1}{10},\frac{3}{10})

Step-by-step explanation:

First we define two generic vectors in our \mathbb{R}^2 space:

  1. v_1 = (x_1,y_1)
  2. v_2 = (x_2,y_2)

By definition we know that Euclidean norm on an 2-dimensional Euclidean space \mathbb{R}^2 is:

\left \| v \right \|= \sqrt{x^2+y^2}

Also we know that the inner product in \mathbb{R}^2 space is defined as:

v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

\left \| v_1 \right \|= \sqrt{x^2+y^2}=1

and

\left \| v_2 \right \|= \sqrt{x^2+y^2}=1

As second condition we have that:

v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0

v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0

Which is the same:

y_1=-3x_1\\y_2=-3x_2

Replacing the second condition on the first condition we have:

\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}

Since x_1^2= \frac{1}{10} we have two posible solutions, x_1=\frac{1}{10} or x_1=-\frac{1}{10}. If we choose x_1=\frac{1}{10}, we can choose next the other solution for x_2.

Remembering,

y_1=-3x_1\\y_2=-3x_2

The two vectors we are looking for are:

v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})

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Answer: 52.489…

Step-by-step explanation:

Angle of elevation is 58 degrees, and the opposite value is 84 feet, so you’re lookin g for adjacent. That means you’ll use tangent to solve this equation:

Tan(58)=84/x

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