Answer:
A. (3 × 4) + (3 × 7)
3(4 + 7)
B. (5 × 9) - (5 × 6)
5(9 - 6)
C. 32 +16 = 48
8 (4 + 2)
D. 4(100 - 3)
97 × 4
E. 7(60 + 6)
66 × 7
Step-by-step explanation:
Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
Answer:
Step-by-step explanation:
Please excuse my handwriting lol.