A circle with center 
and radius 
has equation
If we substitute 
in this equation, we have
This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:
The expression simplifies to
The solutions to the associated equation are
So, the parabola is negative between the two solutions:
Fifth grade algebra<span> and functions worksheets contain math problems with variables.</span>
The Answer is 3 + 4 = 8 - 1
The answer is D. all you have to do is solve for y.
Answer:
the equation would be (x-5)^2 + (y-(-3)^2= 4^2
Step-by-step explanation:
How I got this was you keep the equation and fill in the blanks with the points.
So the first blank with (x-?)^2 would be 5 because that is your x point.
The second blank with (y-(?))^2 would be -3 because that is your y point.
The last blank would be 4^2 because that is your radius
Let me know if you need more
