4 years ago

Slope = four fifths ,y-intercept = -1

1 answer:

5 0

Slope-intercept form:
y=mx+b

m=slope
b=y-intercept

Data:
m=4/5
b=-1

y=mx+b
y=(4/5)x-1

Answer: the equation of the line with slope=4/5, and y-intercept=-1 would be:
y=(4/5)x-1

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P/4+=16<br> Pls show work!!

Dima020 [189]

Answer:

P = 64

Step-by-step explanation:

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3 years ago

Y varies inversley with x y= 0.5 x= 3 what is the value of k the constant of inverse variations

umka2103 [35]

Y varies inversely with x
y = k/x

when y = 0.5, x = 3
0.5 = k/3
k = 0.5 x 3 = 1.5

k = 1.5

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4 years ago

Which points are solutions to the system of inequalities shown below check all that apply y>x+1

Arte-miy333 [17]

The points which satisfy the inequalities in discuss are; Choices D (7,10) and F(8,17).

<h3>Which points omg the answer choices satisfy the system of inequalities?</h3>

It follows from the inequality; x > 5.

Also, substituting 5 for x in; y < 2(x); we have;

y < 10.

Hence, the points which satisfy the inequalities are; (8,17) and (7,10).

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2 years ago

TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title

Norma-Jean [14]

This is easily done after writing both complex numbers in exponential form:

$z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}$

$z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}$

Then

$\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}$

In trigonometric form, this is

$\dfrac{z_1}{z_2}=4\,\mathrm{cis}150^\circ=4(\cos150^\circ+i\sin150^\circ)=\boxed{-\dfrac{\sqrt3}2+\dfrac i2}$

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3 years ago

Use the binomial series to find the maclaurin series for the function. (use (2n)! 2nn! for 1 · 3 · 5 (2n − 1).) f(x) = 1 1 − x5

dlinn [17]

Use the binomial series to find the maclaurin series for the function. (use (2n)! 2nn! for 1 · 3 · 5 (2n − 1).) f(x) = 1 1 − x5 vfdgfdbfdvbcbvcb f fbv vbbvcbvb

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4 years ago