In finding the minimum amount of time that Brandon can swim is to add the quotient of the distance to swim and its velocity and the quotient of the difference of 250 and the distance cover in running and its velocity. The minimum time is 43.33 seconds
Answer:
0.750714286
Step-by-step explanation:
Answer:
horizontal translation 1 unit right and vertical translation 2 unit up
Step-by-step explanation:
we are given


We can see that in place x , we have x-1
So, it is shifted horizontally right side by 1 unit
We have +2 added to f(x)-value
It means 2 is added to y-value
So, it is shifted vertically upward by 2 units
So, horizontal translation 1 unit right and vertical translation 2 unit up
Answer:
Step-by-step explanation:
So, we have-
(6 x .1) + (3 x .01) + (2 x .001)
So, we will solve inside of the parenthesis first.
6 x .1 = <u>.6</u>
So, we got that settled next-
3 x .01 = <u>.03</u>
We got that settled last-
2 x .001 = <u>.002</u>
Lastly, we add them all.
.6 + .03 + .002 = .632
Now we compare.
.632 > .629
So, there is your answer!
Hope this helps!
1)8
2)3
3)1
4)14
the coefficient is the number in front of the variable