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USPshnik [31]
4 years ago
11

4. Estimate the sum of 9.327 + 5.72 + 4.132 to one decimal place.18.729

Mathematics
2 answers:
love history [14]4 years ago
7 0

Answer:

Hence, the estimate value of  9.327 + 5.72 + 4.132 to one decimal place is:

 19.2

Step-by-step explanation:

We have to Estimate the sum of 9.327 + 5.72 + 4.132 to one decimal place

We find the sum of these numbers:

Sum=  9.327+5.72+4.132

      =  19.179

Now we have to estimate the value to one decimal place

  so, on approximating the value, we get the sum=19.2

Hence, the estimate value of  9.327 + 5.72 + 4.132 to one decimal place is:

19.2

ziro4ka [17]4 years ago
6 0
The sum for those numbers is 19.179 NOT 18.729. HOWEVER the Estimation of the sum and the answer for this question is 19.2 because the decimal place you are finding has a number to its right that is greater to that decimal place so you add the one to the decimal place you are finding.
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Answer:

14.3%

Step-by-step explanation:

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8 0
2 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
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Leno4ka [110]

Answer:

quadratic monomial, quadratic trinomial, constant monomial, linear monomial, quadratic binomial, linear binomial.

Step-by-step explanation:

two quadratic trinomials each have a degree-2, degree-1, and degree-0 term. It is possible that the coefficients of all or some of the terms cancel each other while adding or subtracting the polynomials.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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