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3 years ago

6

How do you solve (x+3)-15=7(x-2)+8

2 answers:

-BARSIC- [3]3 years ago

8 0

Solve using BEDMAS
<span>(x+3)-15=7(x-2)+8
</span>x+3-15=7(x-2)+8
x-12=7(x-2)+8
Distribute the Brackets
x-12=7(x-2)+8
x-12=7x-14+8
x-12=7x-6
Add 12 to both sides.
(x-12)+12=(7x-6)+12
x=7x+6
Subtract 7x from both sides
(x)-7x=(7x+6)-7x
-6x=6
Divide both sides by -6
(-6x)/-6=(6)/-6
x= -1

Hope this helps!
-Benjamin

lbvjy [14]3 years ago

6 0

(X+3)-15=7(x-2)+8
X+3-15=7x-14+8
X-12=7x-6
-7x -7x
-6x-12=-6
12 12
-6x/-6 6/-6

Answer: x= -1

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