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Zina [86]
4 years ago
6

Which is the most reasonable conjecture about the data shown in the scatter plot? A. People with larger televisions tend to watc

h more television. B. People with larger televisions tend to watch less television. C. There appears to be no relationship between the size of the television and how many hours it is watched.
Mathematics
2 answers:
Bogdan [553]4 years ago
8 0

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Anastasy [175]4 years ago
3 0
Need scatter plot to help
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The answer to all of these questions
11111nata11111 [884]
The first answer to the question is male . I don’t know about the rest right now because my phone is cracked and I’m having issues seeing the words haha sorry I tried my best .
7 0
4 years ago
Simplify the expression 4p-5p-30p=
Fudgin [204]

Answer:

-31p

Step-by-step explanation:

........

6 0
3 years ago
Read 2 more answers
3
katovenus [111]

Question is Incomplete, Complete question is given below.

Mr. Jablonski's class is making fudge for a bake sale. Mr. Jablonski

has a recipe that makes 3/4 pound of fudge. There are 21 students in

the class. Each student uses the recipe to make one batch of fudge.

How many pounds of fudge do the students make?

Answer:

student made \frac{63}{4} \ lbs \ OR \ 15 \frac{3}{4}\ lbs \ OR \ 15.75\ lbs of fudge.

Step-by-step explanation:

Given:

Mr. Jablonski  recipe makes 3/4 pound of fudge.

Number of student in class = 21 students.

Each student uses the recipe to make one batch of fudge.

Hence to calculate Total amount of fudge student made we will multiply the amount of fudge used in recipe with Number of students.

Total amount of fudge student made = amount of fudge used in recipe × Number of students.

Total amount of fudge student made = \frac{3}{4}\times21 = \frac{63}{4} \ lbs =15 \frac{3}{4}\ lbs = 15.75\ lbs

Hence the student made \frac{63}{4} \ lbs \ OR \ 15 \frac{3}{4}\ lbs \ OR \ 15.75\ lbs of fudge.

8 0
3 years ago
The area of a rectangular parking lot is represented by A = 6x^2 − 19x − 7 If x represents 15 m, what are the length and width o
Mekhanik [1.2K]

Answer:

The length and width of the parking lot are \frac{46}{3} meters and \frac{23}{2} meters, respectively.

Step-by-step explanation:

The surface formula (A) for the rectangular parking lot is represented by:

A = w\cdot l

Where:

w - Width of the rectangle, measured in meters.

l - Length of the rectangle, measured in meters.

Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If A = 6\cdot x^{2}-19\cdot x -7, the factorized form is:

A = \left(x-\frac{7}{2}\,m \right)\cdot \left(x+\frac{1}{3}\,m \right)

Now, let consider that w = \left(x-\frac{7}{2}\,m \right) and l = \left(x+\frac{1}{3}\,m \right), if x = 15\,m, the length and width of the parking lot are, respectively:

w =\left(15\,m-\frac{7}{2}\,m \right)

w = \frac{23}{2}\,m

l =\left(15\,m+\frac{1}{3}\,m \right)

l = \frac{46}{3}\,m

The length and width of the parking lot are \frac{46}{3} meters and \frac{23}{2} meters, respectively.

5 0
3 years ago
Help ASAP I’ll give you guys brainliest tysm:)
LenaWriter [7]

answer will be 20 dollar

4 0
3 years ago
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