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3 years ago

Please help I will mark brainlist if correct

Mathematics

1 answer:

djyliett [7]3 years ago

8 0

Solving for L:

P = 2L + 2W
P - 2W = 2L
(P - 2W) / 2 = L
L = (P - 2W) / 2

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the tank is 600 cubic meters. the height of tank is 6 meters. the base of the tank is square what is the side of the side of the

harkovskaia [24]

Volume (tank)=base x heitht
base is a squeare, so base=side²

Volume(Tank)=side² * height
600 m³=side² * 6 m
side²=600 m³/ 6 m
side²=100 m²
side=√(100 m²)=10 m.

answer: the side of the base is 10 m.

5 0

4 years ago

What is the value of f[g(3)] for the functions f(x) =x+2 and g(x) = 5x - 1

alexdok [17]

Answer:

Step-by-step explanation:

In this case we know the composition of f and g is

$f(g(x))=f(5x-1)=5x-1+2=5x+1$

Thus if we change x by 3 we get

$f(g(3))=5(3)+1=16$

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3 years ago

Solve the following system of inequalities graphically on the set of axes below. State

tankabanditka [31]

Answer:

The answer is definitely C

Step-by-step explanation:

Following the system of inequalities will graph this solution best on the graph, it is the inequality represented in the graph.

ur wlcm :)

correct me if im wrong

brainliest please?

6 0

3 years ago

Give the digits in the ones place and the tenths place <br>23.91

Andru [333]

Answer:

Ones place: 3, Tenths place: 0.9

Step-by-step explanation:

Simple math

8 0

3 years ago

X² - 6x + 4 = 0<br><br> solve and show work. ...?

ycow [4]

The answer is 3 + √5 and 3 - √5.

This is quadratic equation: x² - 6x + 4 = 0
The general quadratic equation is ax² + bx + c = 0
Our equation can be rewritten: 1x² + (-6)x + 4 = 0
So, in our equation we have: a = 1, b = -6, c = 4

Now, x can be calculated using the formula: $x_{1,2}= \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a}$
$x_{1,2} =\frac{-(-6)+/- \sqrt{ (-6)^{2}-4*1*4 } }{2*1} = \frac{6+/- \sqrt{36-16} }{2} = \frac{6+/- \sqrt{20} }{2} =\frac{6+/- \sqrt{4*5} }{2}= \\ 
=\frac{6+/- \sqrt{4}* \sqrt{5} }{2} =\frac{2*3+/- 2\sqrt{5} }{2}= \frac{2(3+/- \sqrt{5}) }{2} =3+/- \sqrt{5}$

From here:
$x_{1} =3+ \sqrt{5} \\ 
x_{2} =3- \sqrt{5}$

6 0

4 years ago