2 years ago

Please help I will mark brainlist if correct

Mathematics

1 answer:

djyliett [7]2 years ago

8 0

Solving for L:

P = 2L + 2W
P - 2W = 2L
(P - 2W) / 2 = L
L = (P - 2W) / 2

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At Westside Middle School, 10 percent, or 140 students, participate in soccer. How many students are in the school? Check all th

Alexeev081 [22]

Answer:

140 + 10 = 150, so 150 + 140 = 290 students. There are 140 + 10 = 150 students at Westside Middle School.

Step-by-step explanation:

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2 years ago

Find the volume of the composite solid. Round your answer to the nearest tenth.

Damm [24]

Answer:

402.12 + 804.24 = 1206.36

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GarryVolchara [31]

The answer is 4 square root 5 or -4 square root 5

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2 years ago

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*

pickupchik [31]

<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation $x^4-41x^2=-400$ .

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

$x^4-41x^2+400=-400+400$ .

$x^4-41x^2+400=0$ .

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

$x^4-25x^2-16x^2+400=0$

Making it into two groups, we get

$(x^4-25x^2)+(-16x^2+400)=0$

Factoring out GCF of each group, we get

$x^2(x^2-25)-16(x^2-25)=0$

$(x^2-25)(x^2-16) =0$

Factoring out $(x^2-25)$ and $(x^2-16)$ separately by difference of the squares identity $a^2-b^2=(a-b)(a+b)$ , we get

$(x^2-25) = x^2-5^2= (x-5)(x+5)$ and

$x^2-16 = x^2-4^2 =(x-4)(x+4)$ .

Therefore,

$(x-5)(x+5)(x-4)(x+4) =0$

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

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2 years ago

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Lemur [1.5K]

29 percent is your answer

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