Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
It will reflect the same distance over the Y axis, from the right side of the graph to the left side of the graph.
Writing equivalent equations help you solve system of equations because it sets it up for being broken down part by part.
Answer:
x = 7
42, 35, 7
Step-by-step explanation:
- EG = 5x+7
- EF = 5x
- FG = 2x-7
Point F is on line segment of EG, therefore EG = EF + FG
- 5x + 7 = 5x + 2x - 7
- 2x = 14
- x = 7
Then
- EG = 5*7 + 7 = 42
- EF = 5*7 = 35
- FG = 2*7 - 7 = 7
The answer should be an acute scalene triangle.
Hope this helped! ♡
