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stiks02 [169]
3 years ago
12

Please help me create a truth table for the statement p^(qv~p)

Mathematics
1 answer:
enyata [817]3 years ago
7 0
Hello,

1)  p∧(q∨¬p)=(p∧q)∨(p∧¬p)=p∧q proof:

2)

p|q|¬p|q∨¬p|p∧(q∨¬p)|p∧q
0|0|..1|.......1|..............0|0
0|1|..1|.......1|..............0|0
1|0|..0|.......0|..............0|0
1|1|..0|.......1|..............1|1



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