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e-lub [12.9K]
3 years ago
5

Determine algebraically wheather or not the function f(x)=-x^3 -2x^2 +5 is even or odd and justify your answer

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

The function f(x) is neither even, nor odd function.

Step-by-step explanation:

<u>Definition: </u>A function is called an even function if for all x from its domain

f(-x)=f(x)

<u>Definition:</u> A function is called an odd function if for all x from its domain

f(-x)=-f(x)

You are given the function f(x)=-x^3-2x^2+5.

Substitute into the function expression -x instead of x.

f(-x)=-(-x)^3-2(-x)^2+5\\ \\f(-x)=-(-x^3)-2x^2+5=x^3-2x^2+5\neq f(x)\\ \\-f(x)=-(-x^3-2x^2+5)=x^3+2x^2-5\\ \\f(-x)\neq -f(x)

Hence, the function f(x) is neither even, nor odd function.

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Read 2 more answers
Mai and Tyler work on the equation 2/5b+1=-11 together. Mais soulution is b=-25 and Tyler’s is b=-28. Here is their work. Do you
Anika [276]

Answer:

No I don't agree with their solution; both their answers are wrong.

Correct answer is b=-30.

Step-by-step explanation:

Given:

\frac{2}{5}b+1=-11

Now given:

According to Mai b = -25 and According to Tyler b = -28

Now we need to find which of them is correct.

So we will solve the given equation we get;

\frac{2}{5}b+1=-11

Subtracting both side by 1 we get;

\frac{2}{5}b+1-1=-11-1\\\\\frac{2}{5}b =-12

Now Multiplying both side \frac{5}{2} we get;

\frac{2}{5}b\times\frac{5}{2}= -12 \times \frac{5}{2}\\\\b=-6\times 5\\\\b=-30

Hence both of them are incorrect, correct answer is b=-30.

3 0
3 years ago
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