All categories

3 years ago

What is negative 2 plus positive two (-2+2) ????

Mathematics

2 answers:

dmitriy555 [2]3 years ago

6 0

Answer:

A_ 1,2,4,5,-1, or,-2

3 plus any of these will always leave you with a positive number of 1-8

B_ -1, -3, -4, -5, or 1

-2 plus any of these will leave you with a negative number of -7 through -1

C_ 1+(-1)

2+(-2)

3+(-3)

4+(-4)

5+(-5)

since all the numbers are 1-5 are both negative and positive these will cancel out and equal to zero.

Step-by-step explanation:

AleksandrR [38]3 years ago

5 0

Answer:

Step-by-step explanation:

(-2+2)

Remove the brackets.

-2+2

= 0

You might be interested in

Write two subtraction equations to show how to find 15 - 7

pantera1 [17]

15-7=8
i hope it helps

5 0

3 years ago

Read 2 more answers

Please help me! Find the number x such that f(x) =1

STatiana [176]

Answer:

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 is less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 is greater than or equal to -2. So, x=1 is also a solution.

Therefore, our two solutions are:

$x_1=-4\text{ or } x_2=1$

Out of our answer choices, we can pick D.

And we're done!

7 0

3 years ago

Suppose M is the midpoint of FG. Find the missing measure.

Arlecino [84]

A midpoint divides a line segment into equal halves.

The value of x is 3.4

Given that:

$FG = 11x - 15.6$

$MG = 10.9$

Since M is the midpoint, then:

$FG = 2 \times MG$

So, we have:

$11x - 15.6 =2 \times 10.9$

$11x - 15.6 =21.8$

Collect like terms

$11x =15.6 +21.8$

$11x =37.4$

Solve for x

$x =3.4$

Hence, the value of x is 3.4