Question

Find the quotient 42j^4 k^2÷(-3j^3 k)

Answer 1

Answer:

$-14jk$

Step-by-step explanation:

We are asked to find the quotient of our given expression $42j^4k^2\div -3j^3k$

First of all, we will write our given problem as a fraction.

$\frac{42j^4k^2}{-3j^3k}$

Using exponent property $\frac{a^m}{a^n}=a^{m-n}$, we will get:

$\frac{42}{-3}(j^{4-3}k^{2-1})$

$-14j^{1}k^{1}$

$-14jk$

Therefore, the quotient of our given problem is $-14jk$.

Answer 2

Your answer is =-14jk