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miskamm [114]
2 years ago
11

If the factors of a quadratic function are (x 2) and (x − 9), what are the x-intercepts of the function?

Mathematics
2 answers:
MArishka [77]2 years ago
7 0

The x-intercepts of the given quadratic function are -2 and 9.

What is a quadratic function?

A quadratic function is a function represented as, f(x) = ax2 + bx + c, with a, b, and c being integers and a not equal to zero. A parabolic curve represents the graph of a quadratic function.

A polynomial's highest degree reveals how many roots the polynomial has. The values for which the polynomial's numerical value is equal to zero are known as a polynomial's roots (also known as zeros of a polynomial). On a graph, the points where the polynomial's graph and the x-axis cross are the roots (x-intercepts).

Roots of the Quadratic Equation

Due to its degree of 2, a quadratic function can only have a maximum of two real roots. In order to find the roots of a quadratic equation, we equate its factors to 0. Thus, in this case, we have,

(x+2)*(x-9)=0

∴ x+2=0

⇒ x=-2

Similarly,

x-9=0

⇒ x=9

Hence, the x- intercepts of the given quadratic function come out to be -2 and 9.

Learn more about a quadratic function here:

brainly.com/question/27958964

#SPJ4

ch4aika [34]2 years ago
5 0

This is my answer i dont know you like it or not

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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Equation of line passing through given points :

Let's proceed with two point form ~

\qquad \sf  \dashrightarrow \: y - y1 =  \cfrac{y2 - y1}{x2 - x1} (x - x1)

Assume :

\qquad \sf  \dashrightarrow \: y - 3=  \cfrac{3 - 3}{ - 4 - 6} (x - 6)

\qquad \sf  \dashrightarrow \: y - 3=  \cfrac{0}{ - 10} (x - 6)

\qquad \sf  \dashrightarrow \: y - 3 = 0

\qquad \sf  \dashrightarrow \: y = 3

So, the equation of required line is : y = 3 ~

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1 year ago
What is coefficient tern and constant  6xy-5xy
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3 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
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Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

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Read 2 more answers
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Answer:

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The total distance, Joshua has to travel, d= 348 miles.

As average speed= (total distance)/(total time)

So, the average speed of driving = 348/6=58 miles/hour

Hence, Joshua must drive at an average speed of 58 miles/hour in order to arrive on time.

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