Answer:
See explanation below to use the vertex form to solve a quadratic equation.
Step-by-step explanation:
(x - h)^2 - k = 0, the vertex is (h, -k)
An example below, taking a quadratic equation and completing the square:
x^2 - 2x - 1 = 0
x^2 - 2x = 1
(-2/-2)^2 = 1, add 1 to both sides of the equation.
x^2 - 2x + 1 = 1 + 1
(x - 1)^2 = 2
(x - 1)^2 - 2 = 0
The vertex is (1, -2)
Answer:
D
Step-by-step explanation:
But basically, one by one you try moving the terms out of the radical.
75 is also 25 * 3 and since 25 has a perfect square root of 5 that goes out and 3 stays inside the radical.
x^3 is also x^2 * x and since x^2 has a perfect square root which is just x that goes outside while the remaining x stays inside.
y^9 is also y^8 * y and since we move variables out the radical in twos y^ goes outside the radical and y stays inside alone.
Finally, z is just z it can't be taken out so it stays inside the radical.
Hope that helps!
F(-6) = 2(-6)+15(-6)-2 = -12-90-2 = -104
Answer:
B - the graph of the function does not form a straight line
Step-by-step explanation:
linear functions have to form a straight line, and that function in the question is a quadratic because x is to the power of 2.
