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3 years ago

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What is the vertex of the graph y = x^2 + 6x - 5 ?

1 answer:

Dafna11 [192]3 years ago

6 0

Given: <span>y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.

The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.

Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:

y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14

Then the vertex is (-3, -14).</span>

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This is a question from my sibling's math class.

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Answer:

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Plzzz Helpp with this!!!!

Travka [436]

f(g(11)) = -6

Solution:

Given data:

$f(x)=x^{2}-6 x+3$

$g(x)=\sqrt{x-2}$

<u>To find f(g(11)):</u>

Substitute x = 11 in g(x).

$g(11)=\sqrt{11-2}$

$=\sqrt{9}$

$g(11)=3$

Substitute g(11) = 3 in f(g(11)).

$f(g(11))=f(3)$

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$f(3)=3^{2}-6 (3)+3$

$f(3)=9-18+3$

$f(3)=-6$

$f(g(11))=f(3)$

= -6

Hence f(g(11)) = -6.

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3 years ago