Answer:
Number of students in vans =15 and bus =46
Step-by-step explanation:
use variables for the vans and buses
let x= vans and y=buses
Now solve the 2 equations simultaneously
<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>
6x+7y=412..........1
6x+9y=504.........2
make x the subject of one equation
and label it equation 3
6x=412—7y

subs 3 into 2





subs 4 into 1





Therefore there are 15 students in each van and 46 students in each bus.
7.211; Starting from the left to right, x1=3 x2=7, y1=2 y2=8. Plug these in to the distance formula
(7-3)^2+(8-2)^2
(4)^2+(6)^2
16+36
sqrt 52
7.211
Answer:
A
Step-by-step explanation:
6/3 = 2
Answer:
<h2><em>
$284.29</em></h2>
Step-by-step explanation:
Let the original price be x
The discounted price for a clearance sale = 30% of x
If the price tag after discounting = $199.
Using the relationship to find the original price x
Original price - discounted price = Current price tag after discounting
x - 0.3x = 199
0.7x = 199
Divide both sides by 0.7
0.7x/0.7 = 199/0.7
x = $284.29
<em>Hence the suit's original price is approximately $284.29</em>
<em />