All categories

3 years ago

Evaluate and simplify if possible:

Mathematics

1 answer:

Yuki888 [10]3 years ago

3 0

$\frac{2x(3y - 4z)}{3(5x + 4z)}$ Plug in the given values
$\frac{2(4)(3(-1) - 4(-3)}{3(5(4) + 4(-3)}$ Multiply where needed
$\frac{8(-3 + 12}{3(20 - 12)}$ Add and subtract inside the parentheses
$\frac{8(9)}{3(8)}$ Multiply
$\frac{72}{24}$
3

You might be interested in

Sara had 97 dollars to spend on 6 books. After

nalin [4]

The answer is 19 6×13 It’s 78-97 you get 19

5 0

2 years ago

Simplify the expression<br> -2(5z -7)

zaharov [31]

-10z+14 would be the simplified answer

4 0

3 years ago

Andrea enjoys running. She keeps a daily journal to record how far she runs. She wears a pedometer to calculate the exact distan

Lana71 [14]

Again this is a simple addition problem I think.

Add 3.6+4.705+5.92=

14.225 kilometers that Andrea ran over the three days.

Hope this helps, have a good day. c;

5 0

2 years ago

Read 2 more answers

Insert geometric means in each geometric sequence.

Digiron [165]

Answer:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the $n^{th}$ term of a geometric sequence.

$a_n=ar^{n-1}$

Where $a$ is the first term and

$r$ is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

$ar = 24\\ar^4 = \dfrac{3}{64}$

Solving the above equation:

$r = \dfrac{1}{8}$

Therefore, the sequence is:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

Considering the second given sequence:

$ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2$

Therefore, the sequence is:

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

Considering the third sequence:

$a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3$

Therefore, the sequence is:

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

5 0

3 years ago

Kelvin's monthly allowance is $42 and Mike's monthly allowance is $63. How many times Mike's monthly allowance is Kelvin's month

earnstyle [38]

It is 1.5 times because $63 divided by $42 is $1.5.
I hope this is what you meant.

3 0

3 years ago