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Oksanka [162]
3 years ago
12

Which set of reflections would carry rectangle ABCD onto itself?

Mathematics
2 answers:
Whitepunk [10]3 years ago
5 0

Answer:

i think that the answer would be but im not 100% sure

Step-by-step explanation:


egoroff_w [7]3 years ago
5 0

Answer with explanation:

The coordinates of vertices of Rectangle A B CD which lies in first Quadrant

    =A(1,1),B(1,3),C(4,3) and D(4,1).

We have to find set of reflections which will carry rectangle ABCD onto itself.

Option-1:

  When we reflect the rectangle along y axis,the rectangle moves in second Quadrant,and when it is reflected through x axis,it goes in Third Quadrant,and when it is reflected through y axis, the rectangle get transferred into fourth quadrant.This set of reflection would not carry rectangle ABCD onto itself.

Option-2:

  When we reflect the rectangle along x axis,the rectangle moves in fourth Quadrant, and when it is reflected through y axis,it goes in Third Quadrant,and when it is reflected through y axis, the rectangle get transferred into fourth quadrant.This set of reflection would not carry rectangle ABCD onto itself.

Option-3

When we reflect the rectangle through x axis, the rectangle moves in fourth quadrant, having vertices A(1,-1),B(1, -3),C(4,-3) and D(4,-1).And when it is reflected through line y=x,the coordinates of rectangle becomes which goes into second quadrant A(-1,1),B(-3,1),C(-3,4) and D(-1,4).Now when the rectangle is reflected through x axis it moves into third Quadrant having vertices A(-1,-1),B(-3,-1),C(-3,-4) and D(-1,-4).Reflecting the rectangle along line , y=x takes it to third Quadrant having vertices A(-1,-1),B(-1,-3),C(-4,-3) and D(-4,-1).This set of reflection would not carry rectangle ABCD onto itself.

Option-4

Reflecting the rectangle along line , y=x gives the vertices of reflected rectangle A(1,1),B(3,1),C(3,4) and D(1,4).Now reflecting this rectangle through x axis takes it to fourth Quadrant having Vertices A(1,-1),B(3,-1),C(3,-4) and D(1,-4).Then reflecting through ,y=x ,takes this rectangle to A(-1,1),B(-1,3),C(-4,3) and D(-4,1),that is into second quadrant.Then reflecting through y axis, takes it to first Quadrant.So, This set of reflection would  carry rectangle ABCD onto itself.

Option D:⇒ y=x, x-axis, y=x, y-axis

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Licemer1 [7]

Answer:

35 dimes and 60 nickels

Step-by-step explanation:

let d = # of dimes and n = # of nickels

We know that Timmy has a total of 95 coins, consisting of dimes and nickels

So d + n = 95

The total value of his bank is $6.50

A dime is worth $0.10 and a nickel is work $0.05

So 0.10d + 0.05n = $6.50

Note that we've just created a system of equations that we can solve

We have the two equations

0.10d + 0.05n = 6.50 and d + n = 95

There are many different methods we can use to solve this system but the easiest way in this situation is probably going to be the substitution method.

First we are going to want to rearrange the terms of the second equations so that one of the variables are defined.

d + n = 95

- subtract d from both sides -

n = 95 - d

We now defined "n"

Now that we have defined one of the variables we can plug in ( or substitute ) the value of it into the other equation. Once we substitute it we can solve for the other variable.

0.10d + 0.05n = 6.50

n = 95 - d

0.10d + 0.05(95 - d) = 6.50

we now solve for d

0.10d + 0.05(95 - d) = 6.50

step 1 distribute the 0.05

0.05 * 95 = 4.75 and 0.05 * -d = -0.05d

0.10d + 4.75 - 0.05d = 6.50

step 2 combine like terms 0.10d  - 0.05d = 0.05d

0.05d + 4.75 = 6.50

step 3 subtract 4.75 from both sides

0.05d = 1.75

step 4 divide both sides by 0.05

0.05d / 0.05 = d and 1.75 / 0.05 = 35

d = 35

Now that we have found the value of one variable we can plug it into one of the equations and solve for the other variable ( note that the equation that we use does not matter, we will acquire the same answer )

d + n = 95

d = 35

35 + n = 95

subtract 35 from both sides

n = 60

We can conclude that he has 35 dimes and 60 nickels

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