Jesus ew math bruh. Anyway let’s sing the campfire
Song
Answer:
5.3624785e+55
Step-by-step explanation:
a. By definition of conditional probability,
P(C | D) = P(C and D) / P(D) ==> P(C and D) = 0.3
b. C and D are mutually exclusive if P(C and D) = 0, but this is clearly not the case, so no.
c. C and D are independent if P(C and D) = P(C) P(D). But P(C) P(D) = 0.2 ≠ 0.3, so no.
d. Using the inclusion/exclusion principle, we have
P(C or D) = P(C) + P(D) - P(C and D) ==> P(C or D) = 0.6
e. Using the definition of conditional probability again, we have
P(D | C) = P(C and D) / P(C) ==> P(D | C) = 0.75
Answer:
Check explanation
Step-by-step explanation:
Here, we want to make a prove;
Mathematically , since D is the midpoint of CE
Then;
CE = CD + DE
Also, since D splits the line segment into two equal parts as the midpoint, then CD must be equal to DE
I.e CD = DE
Hence, we can express CE as follows;
CE = DE + DE
CE = 2 DE
Divide both sides by 2
CE/2 = DE
Hence; DE = 1/2 CE
